Question

我有一个类似于以下内容的select语句：

select *
from A
  inner join B on A.id_x = B.id_x
  inner join C on B.id_y = C.id_y
  inner join D on C.id_z = D.id_z
where
  A.date > '2014-01-01'
  and A.id_y = 154
  and D.id_t = 2

我想要的是做and count(A.id_x) > 1这样的事情，它只返回原始选择中A.id_x重复的部分。

这可能吗？

编辑：

我只是尝试使用临时表来解决它，使用我从T-SQL Insert into table without having to specify every column

获得的代码

Select * Into 
    #tmpBigTable
    From [YourBigTable]

但是我收到了一条错误消息，因为我的表格具有相同的列名，例如A.id_x和B.id_x。

＆＃34;每个表中的列名必须是唯一的。＆＃34;

是否有某种方法可以强制解决问题，或声明任意命名扩展名？

Answer 1

select *
from A
  inner join B on A.id_x = B.id_x
  inner join C on B.id_y = C.id_y
  inner join D on C.id_z = D.id_z
where
  A.date > '2014-01-01'
  and A.id_y = 154
  and D.id_t = 2
  AND  A.id_x IN
  (
  SELECT A.id_x FROM A
  GROUP BY A.id_x
  HAVING count(A.id_x)>1);

Answer 2

您可以使用窗口函数执行此操作：

select *
from (select *, count(*) over (partition by A.id_x) as cnt
      from A inner join
           B
           on A.id_x = B.id_x inner join
           C
           on B.id_y = C.id_y inner join
           D
           on C.id_z = D.id_z
      where A.date > '2014-01-01' and A.id_y = 154 and D.id_t = 2
     ) abcd
where cnt > 1;

仅选择列值出现多次的行

2 个答案: