Question

   TableOne

      PersonId        PersonScore
         1                10
         1                20
         2                99
         2                40
         3                45

我只需要获取PersonId出现超过一次的那些行，例如以下是我想要实现的结果集

     PersonId        PersonScore
         1                10
         1                20
         2                99
         2                40

我正在使用cte

  ;WITH cte AS (
   SELECT  *, ROW_NUMBER() OVER (PARTITION BY i.PersonId ORDER BY i.PersonId) AS [Num]
   FROM    TableOne i
   )
   SELECT  *
   FROM    cte
   WHERE   cte.Num > 1

问题是它删除了额外的行。它是任何PersonId的第一个实例。任何人都可以建议解决方案

Answer 1

您希望将count(*)用作窗口函数，而不是row_number()：

select t.PersonId, t.PersonScore
from (select t.*, count(*) over (partition by PersonId) as cnt
      from TableOne t
     ) t
where cnt > 1;

Answer 2

SELECT *
FROM TableOne t1
JOIN (SELECT PersonId
      FROM TableOne
      GROUP BY PersonId
      HAVING COUNT(*) > 1) t2
on t1.PersonId = t2.PersonId

Answer 3

您可以使用简单的相关子查询：

SELECT PersonId, PersonScore
FROM dbo.TableOne t1
WHERE (SELECT COUNT(*) 
       FROM dbo.TableOne t2 
       WHERE t1.PersonId = t2.PersonID) > 1

选择出现多次的行

3 个答案: