Question

我希望在几分钟内在Netezza中获得时差。

我有两列：Start(2014-06-01 07:45:04)和finish(2014-06-01 07:46:58)个事件

我尝试过使用DATEDIFF(SECOND,start,finish)，但是Netezza发现错误。

我缺少一个功能吗？

Select R.*,S.*,CM.URL,DATEDIFF(SECOND,R.EVENT_DTM,S.MIN) From CTE_1 R 
JOIN CTE_2 S
on S.VISIT_KEY = R.VISIT_KEY
JOIN ADMIN.VW_DIM_CME_METADATA CM on CM.CONTENT_METADATA_KEY = R.CONTENT_METADATA_KEY

Answer 1

在IBM论坛上进行了一些搜索，发现这有效。如果有人有更好的方式，请发布它。感谢

    Select 
    R.*,S.*,CM.URL,
    EXTRACT(EPOCH from S.MIN - R.EVENT_DTM)DIFF 
    From CTE_1 R 
    JOIN CTE_2 S
    on S.VISIT_KEY = R.VISIT_KEY
    JOIN ADMIN.VW_DIM_CME_METADATA CM on CM.CONTENT_METADATA_KEY = R.CONTENT_METADATA_KEY

Answer 2

Alankar的替代方案：

Select 
    R.*,S.*,CM.URL,
    EXTRACT(SECOND from S.MIN - R.EVENT_DTM)DIFF 
    From CTE_1 R 
    JOIN CTE_2 S
    on S.VISIT_KEY = R.VISIT_KEY
    JOIN ADMIN.VW_DIM_CME_METADATA CM on CM.CONTENT_METADATA_KEY = R.CONTENT_METADATA_KEY

Answer 3

https://www-304.ibm.com/connections/forums/html/topic?id=1f1f9bec-9ed4-42f4-9242-c099a8120523建议

提取（来自（timestamp2 - timestamp1）的纪元）

其中一条评论表明另一种选择：

如果您安装Netezza SQL Extension Toolkit，您只需使用即可 seconds_between函数，例如seconds_between（timestamp2， timestamp1）。

Answer 4

我建议使用Netezza SQL Extension Toolkit：

select seconds_between('1996-02-27 06:12:33','1996-02-27 06:55:22');

请参阅Date and Time function reference。

Answer 5

如果您希望两个时间戳之间的符号结果为秒，我建议使用如下表达式。

TESTDB.ADMIN(ADMIN)=> select * from time_diff;
        COL1         |        COL2
---------------------+---------------------
 2014-06-24 21:28:33 | 2014-06-22 21:30:58
(1 row)

TESTDB.ADMIN(ADMIN)=> select extract(epoch from col1) - extract(epoch from col2) diff from time_diff;
  DIFF
--------
 172655
(1 row)

TESTDB.ADMIN(ADMIN)=> select extract(epoch from col2) - extract(epoch from col1) diff from time_diff;
  DIFF
---------
 -172655
(1 row)

如果您对签名结果不感兴趣，那么使用mc110提到的SQL Extension Toolkit提供的seconds_between函数效果很好，或者您可以简单地将ABS函数应用于第一个解决方案。

如果您在当前数据库中安装了SQL Extension Toolkit，则不需要我在此处使用的SQLEXT ..限定符。我碰巧将工具包安装在一个单独的数据库中，我称之为SQLEXT。

TESTDB.ADMIN(ADMIN)=> select abs(extract(epoch from col2) - extract(epoch from col1)) diff from time_diff;
  DIFF
--------
 172655
(1 row)

TESTDB.ADMIN(ADMIN)=> TESTDB.sqlext..seconds_between(col1,col2) diff from time_diff;
  DIFF
--------
 172655
(1 row)

我建议不要使用＆＃34;秒＆＃34;结果你可能不会成为你想要的。同样地使用单个提取物＆＃34; epoch＆＃34;减去两个值的值也可能无法满足您的期望。

TESTDB.ADMIN(ADMIN)=> select extract(seconds from col1 - col2) diff from time_diff;
 DIFF
------
   35
(1 row)

TESTDB.ADMIN(ADMIN)=> select extract(epoch from col1 - col2) diff from time_diff;
  DIFF
--------
 172655
(1 row)

TESTDB.ADMIN(ADMIN)=> select extract(epoch from col2 - col1) diff from time_diff;
  DIFF
---------
 -172654
(1 row)

使用Netezza的秒数时差？

5 个答案: