Question

我是Android Native编码的新手，我有来自我的webservice的xml响应，我很困惑。如何解析xml数据并将数据插入到String数组中..我有一个来自服务器的响应。

<?xml version="1.0" encoding="UTF-8"?>
 <soap:Body>
  <GetActiveThemeListResponse xmlns="http://tempuri.org/">
     <GetActiveThemeListResult>
        <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="NewDataSet">
           <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
              <xs:complexType>
                 <xs:choice minOccurs="0" maxOccurs="unbounded">
                    <xs:element name="ActiveThemeList">
                       <xs:complexType>
                          <xs:sequence>
                             <xs:element name="ThemeName" type="xs:string" minOccurs="0" />
                          </xs:sequence>
                       </xs:complexType>
                    </xs:element>
                 </xs:choice>
              </xs:complexType>
           </xs:element>
        </xs:schema>
        <diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
           <NewDataSet xmlns="">
              <ActiveThemeList diffgr:id="ActiveThemeList1" msdata:rowOrder="0">
                 <ThemeName>sample</ThemeName>
              </ActiveThemeList>
              <ActiveThemeList diffgr:id="ActiveThemeList2" msdata:rowOrder="1">
                 <ThemeName>magic</ThemeName>
              </ActiveThemeList>
              <ActiveThemeList diffgr:id="ActiveThemeList3" msdata:rowOrder="2">
                 <ThemeName>travel</ThemeName>
              </ActiveThemeList>
           </NewDataSet>
        </diffgr:diffgram>
     </GetActiveThemeListResult>
  </GetActiveThemeListResponse>
 </soap:Body>
</soap:Envelope>

如何获取第二个子节点NewDataSet的数据我需要将ThemeName节点值sample插入到array []中; 我需要存储如下数据：

Ex:[sample, magic, travel]

AnyBody帮助将不胜感激......

Answer 1

你可以使用Jsoup

（从here下载 - 只需将jar添加到您的项目中。如果您遇到任何问题，请告诉我们）

要使用它，你会写：

 List<String> themes = new ArrayList<String>();

 // Parse the XML to create a DOM
 Document doc = Jsoup.parse(yourXmlAsAString);

 // Use the select method to select all ThemeName tags
 for (Element elem: doc.select("ThemeName")){

     // Use the text method to get the inner text
     themes.add(elem.text());
 }

如果您想确保Jsoup仅选择ThemeName的{{1}}个标记，请替换

NewDataSet

与

for (Element elem: doc.select("ThemeName")){

Answer 2

另一个选择是使用XmlPullParser。与SAX和DOM相比，它的优点是相对简单的API，并且速度快，并且需要比DOM API更少的内存。请阅读the google doc here 示例如何使用

import java.io.IOException;
import java.io.StringReader;
import org.xmlpull.v1.XmlPullParser;
import org.xmlpull.v1.XmlPullParserException.html;
import org.xmlpull.v1.XmlPullParserFactory;

 public class SimpleXmlPullApp
 {

     public static void main (String args[])
         throws XmlPullParserException, IOException
     {
         XmlPullParserFactory factory = XmlPullParserFactory.newInstance();
         factory.setNamespaceAware(true);
         XmlPullParser xpp = factory.newPullParser();

         xpp.setInput(new StringReader ("<foo>Hello World!</foo>"));
         int eventType = xpp.getEventType();
         while (eventType != XmlPullParser.END_DOCUMENT) {
          if(eventType == XmlPullParser.START_DOCUMENT) {
              System.out.println("Start document");
          } else if(eventType == XmlPullParser.END_DOCUMENT) {
              System.out.println("End document");
          } else if(eventType == XmlPullParser.START_TAG) {
              System.out.println("Start tag "+xpp.getName());
          } else if(eventType == XmlPullParser.END_TAG) {
              System.out.println("End tag "+xpp.getName());
          } else if(eventType == XmlPullParser.TEXT) {
              System.out.println("Text "+xpp.getText());
          }
          eventType = xpp.next();
         }
     }
 }

如何解析Xml数据......？

2 个答案: