大家好我有xml解析的问题我有跟随xml必须解析但我很困惑如何解析这个。我有以下this
<Root>
<Category id="1" name="Live" subcategories="6">
<SubCategory id="1" name="Entertenment" subcategories="0"/>
<SubCategory id="2" name="Movies" subcategories="0"/>
<SubCategory id="3" name="Musics" subcategories="0"/>
<SubCategory id="4" name="Regional" subcategories="0"/>
<SubCategory id="5" name="Devotional" subcategories="0"/>
<SubCategory id="6" name="News" subcategories="4">
<ChildCategory id="1" name="International" subcategories="0"/>
<ChildCategory id="2" name="Politic" subcategories="0"/>
<ChildCategory id="3" name="Movies" subcategories="0"/>
<ChildCategory id="4" name="Celeberities" subcategories="0"/>
</SubCategory></Category>
</Root>
如果有任何解决方案，请建议我。
答案 0 :(得分：1)
使用XMLPullParser。示例代码是解析rss内容。
try {
// Standard code to make an HTTP connection.
URL url = new URL(RSS_URL);
URLConnection connection = url.openConnection();
connection.setRequestProperty("User-agent", "Mozilla/4.0");
connection.setConnectTimeout(20000);
connection.connect();
InputStream in = connection.getInputStream();
XmlPullParserFactory factory = XmlPullParserFactory.newInstance();
factory.setNamespaceAware(true);
XmlPullParser xpp = factory.newPullParser();
xpp.setInput(in, null);
int eventType;
String title = "";
String link = "";
String description = "";
String pubDate = "";
eventType = xpp.getEventType();
while (eventType != XmlPullParser.END_DOCUMENT) {
if (eventType == XmlPullParser.START_TAG) {
String tag = xpp.getName();
if (tag.equals("item")) {
title = link = description = "";
} else if (tag.equals("title")) {
xpp.next();
title = xpp.getText();
} else if (tag.equals("link")) {
xpp.next();
link = xpp.getText();
} else if (tag.equals("description")) {
xpp.next();
description = xpp.getText();
} else if (tag.equals("pubDate")) {
xpp.next();
pubDate = xpp.getText();
}
} else if (eventType == XmlPullParser.END_TAG) {
String tag = xpp.getName();
if (tag.equals("item")) {
description = " "
+ description.replaceAll("<a target.*<br>", "");
RssItem item = new RssItem();
item.mTitle = title;
item.mUrl = link;
item.mDescription = description;
item.mPubDate = pubDate;
item.mMD5 = MD5.getMD5(link.getBytes());
runOnUiThread(new DataInsert(item));
}
}
eventType = xpp.next();
}
} catch (Exception e) {
Log.i(" RssReaderView ", e.getMessage());
e.printStackTrace();
}
答案 1 :(得分：1)
这是从xml解析的示例代码。首先，您创建一个数据库来存储来自xml解析的数据... 试试吧..
dh.delete(Exampl.TABLE, null, null);
try {
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document doc = docBuilder.parse (istream);
doc.getDocumentElement ().normalize ();
System.out.println ("Root element of the doc is " +
doc.getDocumentElement().getNodeName());
NodeList dblist = doc.getElementsByTagName("database");
Element e = (Element) dblist.item(0);
NodeList tab = e.getElementsByTagName("table");
System.out.println(tab.getLength() + " Tabels");
for(int k=0;k<tab.getLength();k++) {
Element el = (Element) tab.item(k);
NodeList col = el.getElementsByTagName("column");
System.out.println("ID is " );
System.out.println();
System.out.println(el.getElementsByTagName("column").item(0).getTextContent());
System.out.println(el.getElementsByTagName("column").item(1).getTextContent());
Category .add(el.getElementsByTagName("column").item(0).getTextContent());
subCategory .add(el.getElementsByTagName("column").item(1).getTextContent());
}
}catch (Exception err) {
err.printStackTrace();
}
for (int j = 0; j < (Category .size()); j++) {
ContentValues questionValues = new ContentValues();
System.out.println(Category .get(j));
questionValues.put("Category ", Category .get(j));
questionValues.put("subCategory ", subCategory .get(j));
dh.insert(Example.TABLE, null,
questionValues);
}
}
答案 2 :(得分：0)
我遇到了同样的问题，我使用XMLPullParser。您可以逐个解析xml节点＆amp;将它们存储到hashmap＆amp;如果有任何相同的标签，你可以将它们存储在载体
中答案 3 :(得分：0)
使用此
进行检查public class MyXmlHandler extends DefaultHandler{
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
if(qName.equalsIgnoreCase("Category")){
// do something
String id = attributes.getValue("id")));
String name = attributes.getValue("Name")));
String subcategories = attributes.getValue("subcategories")));
}else if(qName.equalsIgnoreCase("SubCategory")){
// do something
String id = attributes.getValue("id")));
String name = attributes.getValue("Name")));
String subcategories = attributes.getValue("subcategories")));
}else if(qName.equalsIgnoreCase("ChildCategory")){
// do something
String id = attributes.getValue("id")));
String name = attributes.getValue("Name")));
String subcategories = attributes.getValue("subcategories")));
}
}
public void endElement(String uri, String localName, String qName)
throws SAXException {
if(qName.equalsIgnoreCase("Category ")){
//Do something
}if(qName.equalsIgnoreCase("subCategory ")){
//Do something
}
if(qName.equalsIgnoreCase("ChildCategory ")){
//Do something
}
}
/* (non-Javadoc)
* @see org.xml.sax.helpers.DefaultHandler#characters(char[], int, int)
*/
public void characters(char[] ch, int start, int length)
throws SAXException {
// TODO Auto-generated method stub
}
}
答案 4 :(得分：0)
试试这个
public class MyXmlHandler extends DefaultHandler{
boolean isCategory, isChildCategory,isSubCategory = false;
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
if(qName.equalsIgnoreCase("Category"))
{
isCategory = true;
String id = attributes.getValue("id");
}else if(qName.equalsIgnoreCase("SubCategory"){
isSubCategory =true;
String id = attributes.getValue("id");
}else if(qName.equalsIgnoreCase("ChildCategory")){
// do something
String id = attributes.getValue("id");
isChildCategory =false;
}
}
public void endElement(String uri, String localName, String qName)
throws SAXException {
if(qName.equalsIgnoreCase("Category ")){
isCategory = false;
}if(qName.equalsIgnoreCase("subCategory ")){
isSubCategory = false;
}
if(qName.equalsIgnoreCase("ChildCategory ")){
isChildCategory =false;
}
}
/* (non-Javadoc)
* @see org.xml.sax.helpers.DefaultHandler#characters(char[], int, int)
*/
public void characters(char[] ch, int start, int length)
throws SAXException {
String value = new String(ch,start,length);
if(isCategory)
{
String str = value;
}
if(isSubCategory)
{
String str1 = value;
}
}
}
////////
//TO call MyXmlHandler
try{
SAXParserFactory spf=SAXParserFactory.newInstance();
SAXParser sp=spf.newSAXParser();
XMLReader xr=sp.getXMLReader();
MyXmlHandler datahandler=new MyXmlHandler();
xr.setContentHandler(datahandler);
xr.parse(new InputSource("url"));
}catch(Exception e)
{
Log.e("SAX XML", "i solve error");
}
答案 5 :(得分：-1)
你可以使用简单的XML解析器库，它很容易在android中使用。你必须在你的代码中创建相关的类和对象。你可以按照链接来理解它 http://robertmassaioli.wordpress.com/2011/04/21/simple-xml-in-android-1-5-and-up/