Question

我一直在使用Synth软件包（使用optimx进行优化），我找不到Synth在不收敛时是否会出现非收敛错误的答案。我可以在optimx的帮助文件中看到，默认情况下，它不会保存失败（即那些不收敛的答案）所以我猜测默认情况下它不会将这些失败传递给Synth;但是，我想确保我得到的答案已经收敛。有没有办法通过convcode（）设置或其他什么来确定这一点？

Answer 1

我查看了代码并且它没有为save.failures设置控件值所以它应该使用optimx的默认行为，因为你已经知道它是假的。以下是optimx代码中对synth()的相关调用。

rgV.optim.1 <- optimx(par = SV1, fn = fn.V, gr = NULL, 
    hess = NULL, method = optimxmethod, itnmax = NULL, 
    hessian = FALSE, control = list(kkt = FALSE, starttests = FALSE, 
        dowarn = FALSE, all.methods = all.methods), X0.scaled = X0.scaled, 
    X1.scaled = X1.scaled, Z0 = Z0, Z1 = Z1, quadopt = quadopt, 
    margin.ipop = Margin.ipop, sigf.ipop = Sigf.ipop, 
    bound.ipop = Bound.ipop)

....

rgV.optim.2 <- optimx(par = SV2, fn = fn.V, gr = NULL, 
    hess = NULL, method = optimxmethod, itnmax = NULL, 
    hessian = FALSE, control = list(kkt = FALSE, 
      starttests = FALSE, dowarn = FALSE, all.methods = all.methods), 
    X0.scaled = X0.scaled, X1.scaled = X1.scaled, 
    Z0 = Z0, Z1 = Z1, quadopt = quadopt, margin.ipop = Margin.ipop, 
    sigf.ipop = Sigf.ipop, bound.ipop = Bound.ipop)

R中的optimx / Synth中的转换代码

1 个答案: