Question

public static void evenSumMax(Scanner console){
      System.out.print("How many integers?");
       int a=console.nextInt();
      int sum=0;
       for(int i=1;i<=a;i++){
      System.out.print("Next integer?");
      int v=console.nextInt();
      if(i%2==0){
      sum=sum+v;
      }else{

      }

       }
      System.out.println("Sum of even is "+sum);



      }

以及如何在for循环中找到最大偶数？

我需要编写System.out.print（“maximum even is”+ ????）;

Answer 1

您可以尝试使用以下代码：

public static void evenSumMax(Scanner console){
   System.out.print("How many integers?");
   int a=console.nextInt();
   int maxEven = 0;
   for(int i=1;i<=a;i++){
      System.out.print("Next integer?");
      int v=console.nextInt();
      if(v%2==0){
          if(v > maxEven)
              maxEven = v;
      }

   }
   System.out.println("Maximum even is " + maxEven);
}

Answer 2

您可以使用:(添加到现有代码中）

public static void evenSumMax(Scanner console) {
    System.out.print("How many integers?");
    int a = console.nextInt();
    int sum = 0;
    int max = Integer.MIN_VALUE; // the smallest value possible in 32-bit integer
    for (int i = 1; i <= a; i++) {
        System.out.print("Next integer?");
        int v = console.nextInt();
        // assuming you're looking for max odd number in input numbers
        if (v % 2 == 0 && v > max) {
            max = v;
        }
        if (i % 2 == 0) {
            sum = sum + v;
        } else {}
    }
    System.out.println("Sum of even is " + sum);
    System.out.print("maximum even is "+ max);
}

Answer 3

以下内容有效。检查输入值的条件后，将其添加到sum变量并将其与maxInt进行比较。如果输入的数字大于先前输入的数字，则将maxInt设置为新值。

 public static void evenSumMax(Scanner console){

  System.out.print("How many integers?");

  int a=console.nextInt();
  int sum=0;
  int maxInt=0;

  for(int i=0;i<a;i++)
  {

  System.out.print("Next integer?");
  int v=console.nextInt();

  if(v%2==0){
  sum=sum+v;

   if(maxInt<v){
       maxInt=v;
               }

           }
   }




  System.out.println("Sum of even is "+sum);
  System.out.println("Maximum even number is "+maxInt);


  }

在for循环中找到最大数量

3 个答案: