Question

我有一些对象的数组，我想以某种方式组织它们

这是我在JavaScript中的数组：

  doctors =       [
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:00"},
  {"prop":"B","hour":"08:00"},
  {"prop":"B","hour":"08:00"},
  {"prop":"B","hour":"08:00"},
  {"prop":"C","hour":"08:00"},
  {"prop":"C","hour":"08:00"}       ]

这个数组来自我的后端（PHP）的ajax调用，我想把它改成这样：

   doctors = [
{"prop":"A",
"hour":"10:00"
"hour":"12:00"
"hour":"23:00"
"hour":"12:00"
"hour":"02:00"
"hour":"01:00"
},

{"prop":"B",
"hour":"18:00"
"hour":"03:00"
"hour":"01:00"
"hour":"08:00"
},

{"prop":"C",
 "hour":"04:00"
 "hour":"12:00"
 "hour":"08:12"
 "hour":"04:00"
 },
 ]

我该怎么做？我的意思是提取类似的键并将所有类似的键压缩成一个值数组???

如果它是importtant，这是我在PHP中的后端：

   if($result = $db->query($sql)){
    $hours = array();

    while($row = $result->fetch_object()){
        $drid = $row->id;
        $hour = $row->b_h;
        $matid = $row->mid;
        $month = $row->b_m;
        $day = $row->b_d;
        $hours[] = [
            'prop'=>$drid.'-'.$matid.'-'.$month.'-'.$day,
            'hour'=>$hour
        ];
    }


    echo (json_encode($hours)) ;

}

数字并不真实，为简单起见，我将真正的道具更改为A B C

如果它有所帮助，稍后，我想在角度js中使用ng-repeat中的每个道具是这样的：

 <li ng-repeat="hour in propA">hour</li>

或者：

 <li ng-repeat="hour in propB">hour</li>

感谢

Answer 1

编辑以适应更改的问题

var doctors =       [
  {"prop":"A","hour":"08:00"},
  {"prop":"A","hour":"08:10"},
  {"prop":"A","hour":"08:20"},
  {"prop":"A","hour":"08:30"},
  {"prop":"A","hour":"08:40"},
  {"prop":"A","hour":"08:50"},
  {"prop":"B","hour":"09:00"},
  {"prop":"B","hour":"09:10"},
  {"prop":"B","hour":"09:20"},
  {"prop":"C","hour":"10:00"},
  {"prop":"C","hour":"10:10"}       ];


var doctors_morph = {};
for(var i in doctors) {
    if(typeof doctors_morph[doctors[i].prop] == 'undefined') {
        doctors_morph[doctors[i].prop] = [];
    }
    doctors_morph[doctors[i].prop].push(doctors[i].hour);

}

这样你可以通过以下方式获得医生：

doctors_morph['A'];
doctors_morph['B'];
doctors_morph['C'];

您的示例结果如下所示：

doctors_morph = {
'A' : {
        ['8:00','8:10','8:20','8:30','8:40','8:50']
    }
// etc
}

AS for PHP，要跳过上面你可以使用：

if($result = $db->query($sql)){
    $doctors = array();
    while($row = $result->fetch_object()){
        $drid = $row->id;
        $hour = $row->b_h;
        $matid = $row->mid;
        $month = $row->b_m;
        $day = $row->b_d;

        if(!isset($doctors[$drid.'-'.$matid.'-'.$month.'-'.$day]) OR !is_array($doctors[$drid.'-'.$matid.'-'.$month.'-'.$day]))
            $doctors[$drid.'-'.$matid.'-'.$month.'-'.$day] = array();

        $doctors[$drid.'-'.$matid.'-'.$month.'-'.$day][] = $hour;

    }


    echo (json_encode($doctors)) ;

}

如何根据javascript中的相似性过滤（提取）数组中的对象？

1 个答案: