Leap Motion:如何在每次滑动时仅滑动一次触发功能?

时间:2014-05-26 14:13:56

标签: javascript audio-player leap-motion

我正在构建一个跳跃运动控制的音乐播放器,菜单系统通过跳跃运动进行控制。

向上和向下滚动菜单项,向右滑动选择该项,向左滑动返回菜单级别。

我遇到的问题是当您向右滑动“艺术家列表”时。菜单,然后更改为歌曲'菜单,因为跳跃动作滑动手势在帧上工作,它会多次触发我的功能,所以第一首歌就会被立即选中。

以下是相关代码:

var updateSelection = function() {
  if(Math.floor(x) == x && $.isNumeric(x)){
    var listLength = $(menu + ' li').size();
    if (x > listLength) x = listLength;
    if (x < 1) x = 1;
    $(menu + ' li').removeClass('active');
    $(menu + ' #' + x + artist ).addClass('active');
     scrollToIt = x + artist;
     idTagX = x;
     if (scrollDirection == "down") {
      var topPos = document.getElementById(scrollToIt).offsetTop;
      document.getElementById('cssmenu').scrollTop = topPos;
      //document.getElementById(scrollToIt).scrollIntoView();
    }
    else if (scrollDirection == "up"){
      var topPos = document.getElementById(scrollToIt).offsetTop;
      document.getElementById('cssmenu').scrollTop = topPos;
      //document.getElementById(scrollToIt).scrollIntoView(true);
    }
  }
}
if(frame.hands.length > 0)
{
  var hand = frame.hands[0];

  pitchRadians = hand.pitch();

  if (pitchRadians > 0.45) {
   newX = x - 0.1;
   x = roundNumber(newX, 2);
   scrollDirection = "up";
   updateSelection();
 }
 else if (pitchRadians < -0.45){
  newX = x + 0.1;
  x = roundNumber(newX, 2);
  scrollDirection = "down";
  updateSelection();
}
else {
  x = parseInt(x);
  updateSelection();
}

}
//--------------------------------------------------Swipe Selection
if (frame.gestures.length > 0) {
  for (var i = 0; i < frame.gestures.length; i++) {
    var gesture = frame.gestures[i];

    //---- Swipe ----
    if (gesture.type == "swipe") {
      var isHorizontal = Math.abs(gesture.direction[0]) > Math.abs(gesture.direction[1]);
      if(isHorizontal){
        if(gesture.direction[0] > 0){

          $(menu + ' #' + idTagX + artist).click();

          console.log(artist);
        } else {
          console.log("Menu Left");
         // $("#" + artist).hide();
          //menu = ".artists"
        }
      } else {
        // Vertical swipe              
      }
    }
  }
}


})

这可能是一个简单的解决方法,我刚刚看了这段代码太久了,无法理解它。

1 个答案:

答案 0 :(得分:2)

我已经为此编写了一个解决方案,详情如下,回答以便其他用户可以查看以供将来参考。

var prevSwipe = "";
var d = new Date();
var now = d.getTime();
var prevSwipeTime = now;


function rightSwipe () {
          d = new Date();
         if(prevSwipe == "right") {
                    if(prevSwipeTime + 1000 < d.getTime()) { //time elapsed, run code
                              $(menu + ' #' + idTagX + artist).click();
                              prevSwipe = "right";
                              prevSwipeTime = d.getTime();
                              console.log("prev == right");
                    } // otherwise do nothing
          } else {
                   $(menu + ' #' + idTagX + artist).click();
                    prevSwipe = "right";
                    prevSwipeTime = d.getTime();
                    console.log(prevSwipeTime);
                    console.log("prev != right");
          }
}

希望这有助于某人!