C ++子结构

Question

嘿，我想得到一些子结构方面的帮助。 我按照以下说明锻炼身体： 那里有1个图书馆

在该图书馆中有10位作者（书籍作者）

每位图书作家最多可以有15本书。

我必须使用2个功能：                        - 阅读所有信息                        - 从A到Z排序书籍

我写了结构，现在我因为子结构而迷失了如何读取它们

代码在这里：http://pastebin.com/gMaZXR89

那我走了多远，我被困在那些＆＃34;得到＆＃34;。 我将不胜感激任何帮助，谢谢

Answer 1

我想我解决了你的问题......

#include <iostream>
#include <stdio.h>
#include <cstring>
using namespace std;

struct Book
{
    char title[30];//unneceserly use Author author[30] because you refer at the book by its author
    float price;
    int year_of_publication;
};

struct Author
{
    char name[30],subname[30];
    int birth_date;
    Book x[14];//a max of 15 books/author
};

struct Library
{
    /*there are 10 book writers*/Author y[9];//because you defined struct Author now you can use it without struct.
};

void readBooks(struct Library lib/*there is a single library*/, const int n=10)//there are 10 book writers
{
    int i,j,how_many;
    for(i=0;i<n;i++)
    {
        cout<<"Input "<<i+1<<". authors name"<<endl;
        gets(lib.y[i].name);//you call the array y not the type Author...
        cout<<"Input "<<i+1<<". authors subname"<<endl;
        gets(lib.y[i].subname);
        cout<<"How many books author"<<i+1<<" write?";
        cin>>how_many;

        for(j=0;j<how_many;++j)
           {
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book title "<<endl;
              gets(lib.y[i].x[j].title);
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book price "<<endl;
              cin>>lib.y[i].x[j].price;
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book year of publication "<<endl;
              cin>>lib.y[i].x[j].year_of_publication;
           }
    }
}
int main()
{
    Library l;//can`t write struct in front because it is defined up...
    readBooks(l);
    return 0;
}

Answer 2

你的问题在于

gets(tab[i].Author[y].name);
gets(tab[i].Author[y].subname);

Author不是您在Library结构中定义的Author类型的结构数组的名称，它的名称是y。

所以它应该是这样的：

   gets(tab[i].y[j].name);
   gets(tab[i].y[j].subname);

祝你好运。