Question

我正在使用python和pygame进行多项选择测验游戏。我有圆圈，当你点击圆圈它会改变宽度并使圆圈变满时需要的是什么。但我不知道可以做到这一点的python函数

到目前为止我的代码：

    # Controls the width of the circles
    width_1 = 2
    width_2 = 2
    width_3 = 2
    width_4 = 2

    # Circles
    pygame.draw.circle(screen, BLACK, [250, 230], 7, width_1)
    pygame.draw.circle(screen, BLACK, [250, 260], 7, width_2)
    pygame.draw.circle(screen, BLACK, [250, 290], 7, width_3)
    pygame.draw.circle(screen, BLACK, [250, 320], 7, width_4)

    for event in pygame.event.get():
        if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:

我希望有一些东西，以便鼠标悬停在圆圈上并按下鼠标按钮并且event.button == 1然后将宽度更改为0（填写）

提前致谢！

P.S。这不是我的全部代码

Answer 1

你可以这样做 x，y = pygame.mouse.get_pos（）打印（x＆amp; y）

让我们说我们想要从一个位置到另一个位置制作一些飞行模块。我们可以做这样的事情

import pygame
from pygame import *
import sys, random, math, fractions

pygame.init()
Screen_Width = 800
Screen_Height = 600

Total_Display = pygame.display.set_mode((Screen_Width, Screen_Height))

clock = pygame.time.Clock()

class Blocks(pygame.sprite.Sprite):
    def __init__(self, width, height):
        super().__init__()
        all_sprite_list.add(self)
        block_list.add(self)
        self.image = pygame.Surface((32,32))
        self.rect = self.image.get_rect()
        self.change_y = 0
        self.change_x = 0

    def blockMove (self, cursor_pos_x, cursor_pos_y, player_pos_x, player_pos_y):

        block_vec_x = cursor_pos_x - player_pos_x
        block_vec_y = cursor_pos_y - player_pos_y
        vec_length = math.sqrt(block_vec_x ** 2 + block_vec_y ** 2)
        block_vec_y = (block_vec_y / vec_length) * 5
        block_vec_x = (block_vec_x / vec_length) * 5
        self.change_y += block_vec_y
        self.change_x += block_vec_x

    def update(self):

        self.rect.y += self.change_y
        self.rect.x += self.change_x

现在很好地创建一个简单的玩家类，只是为了将块发射到鼠标位置，将其放置在窗口中间！

class Player(pygame.sprite.Sprite):
    def __init__(self):
        player_list.add(self)
        self.rect = Rect(400,300,16,16)
        self.image = pygame.surface((16,16))

all_sprite_list = pygame.sprite.Group()
player_list = pygame.sprite.Group()
block_list = pygame.sprite.Group()

block = Blocks(16,16)
player = Player()

running = True
while running:
    clock.tick(60)

    for e in pygame.event.get()
        if e == pygame.Quit:
            running = False
        if e.type == pygame.KEYDOWN and e.type == pygame.K_ESCAPE:
            running = False

这里我们得到鼠标位置我们设置Mouse_X和Mouse_Y = mouse.get_pos（）将输出（x，y）或Mouse_X =鼠标pos x和Mouse_Y =鼠标pos y。您还可以通过添加打印件来放置鼠标的位置（Mouse_x＆amp;＆＃34;＆＃34;＆amp; Mouse_y）

    Mouse_x, Mouse_y = pygame.mouse.get_pos()
    key = pygame.key.get_pressed()
    if key[pygame.K_SPACE]:
        block = Blocks(16,16)
        block.blockMove(Mouse_x, Mouse_y, player.rect.x, player.rect.y)
        block.rect.x = player.rect.x
        block.rect.y = player.rect.y
    block.update()
    Total_Display.fill((255,0,0))
    for sprite in all_sprite_list:
        pygame.draw.rect(Total_Display,(0,0,0), sprite)
    for blocks in block_list:
        pygame.draw.rect(Total_Display, (0,0,0), block)

    pygame.display.flip()

我可能有点过火但是希望这可以帮助那里的人！

这就是确保我没有犯错的全部内容

import pygame
from pygame import *
import sys, random, math, fractions

pygame.init()
Screen_Width = 800
Screen_Height = 600

Total_Display = pygame.display.set_mode((Screen_Width, Screen_Height))

clock = pygame.time.Clock()

class Blocks(pygame.sprite.Sprite):
    def __init__(self, width, height):
        super().__init__()
        all_sprite_list.add(self)
        block_list.add(self)
        self.image = pygame.Surface((32,32))
        self.rect = self.image.get_rect()
        self.change_y = 0
        self.change_x = 0

    def blockMove (self, cursor_pos_x, cursor_pos_y, player_pos_x, player_pos_y):

        block_vec_x = cursor_pos_x - player_pos_x
        block_vec_y = cursor_pos_y - player_pos_y
        vec_length = math.sqrt(block_vec_x ** 2 + block_vec_y ** 2)
        block_vec_y = (block_vec_y / vec_length) * 5
        block_vec_x = (block_vec_x / vec_length) * 5
        self.change_y += block_vec_y
        self.change_x += block_vec_x

    def update(self):

        self.rect.y += self.change_y
        self.rect.x += self.change_x

class Player(pygame.sprite.Sprite):
    def __init__(self):
        super().__init__()
        player_list.add(self)
        all_sprite_list.add(self)
        self.rect = Rect(400,300,16,16)
        self.image = pygame.Surface((16,16))


all_sprite_list = pygame.sprite.Group()
player_list = pygame.sprite.GroupSingle()
block_list = pygame.sprite.Group()

block = Blocks(16,16)
player = Player()

running = True
while running:
    clock.tick(60)


    for e in pygame.event.get():
        if e == pygame.QUIT:
            Running = False
        if e.type == pygame.KEYDOWN and e.type == pygame.K_ESCAPE:
            running = False

    Mouse_x, Mouse_y = pygame.mouse.get_pos()
    key = pygame.key.get_pressed()
    if key[pygame.K_SPACE]:
        block = Blocks(16,16)
        block.update()
        block.blockMove(Mouse_x, Mouse_y, player.rect.x, player.rect.y)
        block.rect.x = player.rect.x
        block.rect.y = player.rect.y
    block.update()
    Total_Display.fill((255,0,0))
    for sprite in all_sprite_list:
        pygame.draw.rect(Total_Display,(0,0,0), sprite)
    for blocks in block_list:
        pygame.draw.rect(Total_Display, (0,0,0), block)

    pygame.display.flip()

Answer 2

您可以使用pygame.mouse.get_pos()（docs）

pygame.mouse.get_pos()获取鼠标光标位置get_pos（） - ＆gt; （X，   y）

  返回鼠标光标的X和Y位置。这个职位是   相对于显示屏的左上角。光标位置   可以位于显示窗口之外，但始终是   限制在屏幕上。

Answer 3

嗯，首先，你需要鼠标坐标。你可以这样做：

mousex, mousey = pygame.mouse.get_pos()

然后你需要一个能检查鼠标是否在圆圈内的功能。要做到这一点，你需要一个圆圈的hitbox。圆形的命中框很难制作，因此您可以通过执行以下操作来使用正方形：

def check_pressed ():
    mousex, mousey = pygame.mouse.get_pos()
    click = pygame.mouse.get_pressed()

    if click != (0, 0, 0):
        if mousex >= buttonx and mousex <= buttonx + button_width and 
        mousey >= buttony and mousey <= buttony + button_height:
            #run function to make button bigger and run a clicked event

将此check_pressed函数添加到主循环中。希望这有帮助！

pygame如何检查鼠标坐标

3 个答案:

这就是确保我没有犯错的全部内容