为什么request.ParseForm()会耗尽request.Body?

时间:2014-05-21 02:50:26

标签: go http-request

在此代码中,如果我评论ParseForm()调用请求按预期工作

package main

import (
    "fmt"
    "net/http"
    "net/url"
    "strings"
)

func main() {

    v := make(url.Values)
    v.Set("status", "yeah!")
    request, error := http.NewRequest("POST", "http://httpbin.org/post", strings.NewReader(v.Encode()))
    if error != nil {
        fmt.Println(error)
    }

    request.Header.Set("Content-Type", "application/x-www-form-urlencoded")
    err:=request.ParseForm()
    if err != nil {
        fmt.Println(err)    
    }
    fmt.Println(request.Form["status"])

    response, error := http.DefaultClient.Do(request)
    if error != nil {
        fmt.Println(error)
    } else {
        fmt.Println(response)
    }
}

但如果我调用ParseForm(),身体就会被清除,我得到:

Post http://httpbin.org/post: http: Request.ContentLength=14 with Body length 0

就像身体长度已经耗尽。如何访问表单值?我需要创建一个请求的签名。还有其他方法(直接从参数直接创建签名?)

1 个答案:

答案 0 :(得分:1)

使用 ParseForm 来读取请求,而不是设置 对于简单的POST,你可以这样做:

resp, err := http.PostForm("http://example.com/form", url.Values{"key": {"Value"}, "id": {"123"}})

http://golang.org/pkg/net/http/#Post
http://golang.org/pkg/net/http/#PostForm