Question

一组阵列扫雷游戏的另外两个问题

1。）我的代码（与Merlin的辅导）正在输出正确数量的地雷。有时。我怎样才能解决这个问题？的 ANSWERED

示例：

Enter width of board: 5
Enter height of board: 5
Enter number of mines: 5
   0  1  2  3  4
0| .  .  .  .  . 
1| .  .  .  .  . 
2| .  .  .  .  * 
3| .  .  *  .  . 
4| *  .  .  *  * 

Enter width of board: 5
Enter height of board: 5
Enter number of mines: 5
   0  1  2  3  4
0| *  .  .  .  . 
1| .  .  *  .  . 
2| .  .  .  .  . 
3| .  *  .  .  . 
4| *  .  .  .  *

MineField代码：

public MineField(int w, int h, int m)
{
    Random r = new Random();
    mineField = new State[w][h];
    surroundingMines = new int[w][h];
    initialiseMineField = new int[w][h];
    traceOn = true; //set to false before submitting
    width = w;
    height = h;
    mineCount = m;
    for (int i = 0; i < w; i++)
    {
        for (int j = 0; j < h; j++)
        {
            mineField[i][j] = State.COVERED;
        }
    }
    for (int k = 0; k < m; k++)
    {
        while (true)
        {
            int a = r.nextInt(w);
            int b = r.nextInt(h);
            if (mineField[a][b] != State.MINED)
            {
                break;
            }
        }
        mineField[r.nextInt(w)][r.nextInt(h)] = State.MINED;
    }
}

状态枚举：

public enum State {
    /** Cell is mined */
    MINED,
    /** Player uncovered (hit) mine */
    EXPLODED,
    /** Cell is not mined but unexplored */
    COVERED,
    /** Cell is not mined and has been explored */
    CLEARED,
    /** Cell has been flagged and contains a mine */
    FLAGGED,
    /** Cell has been flagged but does not contain a mine */
    MISFLAGGED;

必填状态字符：

public char toChar(int surroundingMines, boolean showTruth) {
    switch (this) {
        case EXPLODED: return '+';
        case COVERED: return '.';
        case CLEARED: return surroundingMines == 0 ? ' ' : String.valueOf(surroundingMines).charAt(0);
        case FLAGGED: return 'F';
        case MINED: return showTruth ? '*' : '.';
        default /* MISFLAGGED */: return showTruth ? 'x' : 'F';
    }
}

2。）我如何能够在我的数组输出中显示围绕单元格的地雷：

   0  1  2  3  4
0| .  .  .  .  . 
1| .  .  .  .  . 
2| .  .  .  .  * 
3| .  .  *  .  . 
4| *  .  .  *  *

使用：

   0  1  2  3  4
0| .  .  .  .  . 
1| .  .  .  1  1 
2| .  .  1  2  * 
3| 1  2  *  2  2 
4| *  1  2  *  *

Answer 1

oops

for (int k = 0; k < m; k++)
{
    while (true)
    {
        int a = r.nextInt(w);
        int b = r.nextInt(h);
        if (mineField[a][b] != State.MINED)
        {
            mineField[a][b] = State.MINED;
            break;
        }
    }
}

2D阵列扫雷随机矿井对象＆amp;周围的地雷

1 个答案: