Question

我正在尝试为自己创建一个计算器。我不知道如何制作它，以便当用户输入例如6为提示允许用户输入6个数字。因此，如果我写了7，它会给我一个选项来写7个数字，然后给我答案，如果我写了8，它会让我写8个数字......

if choice == "2" then
    os.execute( "cls" )
    print("How many numbers?")
    amountNo = io.read("*n")
    if amountNo <= 2 then print("You cant have less than 2 numbers.")
    elseif amountNo >= 14 then print("Can't calculate more than 14 numbers.")
    elseif amountNo <= 14 and amountNo >= 2 then
        amountNmb = amountNo
        if amountNmb = 3 then print(" Number 1")
        print("Type in the numbers seperating by commas.")
    local nmb
    print("The answer is..")

Answer 1

io.read格式有点限制。

如果你想要输入以逗号分隔的列表，我建议读一整行，然后遍历每个值：

local line = io.input("*l")
local total = 0
-- capture a sequence of non-comma chars, which then might be followed by a comma
-- then repeat until there aren't any more
for item in line:gmatch("([^,]+),?") do 
    local value = tonumber(item) 
    -- will throw an error if item does not represent a number
    total = total + value
end 
print(total)

这不会将值的数量限制为任何特定值 - 即使空列表也可以。（它有缺陷的是它允许行以逗号结束，这将被忽略。）

Answer 2

根据我的理解，您want the following：

print "How many numbers?"
amountNo = io.read "*n"
if amountNo <= 2 then
    print "You can't have less than 2 numbers."
elseif amountNo >= 14 then
    print "Can't calculate more than 14 numbers."
else
    local sum = 0
    for i = 1, amountNo do
        print( ('Enter number %s'):format(i) )
        local nmb = io.read '*n'
        sum = sum + nmb
    end
    print( ('The sum is: %s'):format(sum) )
end

Answer 3

如果用户用逗号分隔数字，他们不需要说明他们想要添加的数量，您可以使用gmatch获取所有数字。使用正确的模式，您可以确保只获得数字：

local line = io.input() 
local total = 0
-- match any number of digits, skipping any non-digits
for item in line:gmatch("(%d+)") do 
    total = total + item
end

输入＆＃4; 6,1,9,10,34＆＃39; （没有引号），然后print(total)给出64，正确答案

Lua与计算器脚本

3 个答案: