Question

我有这个SQL查询：

SELECT 
  *,
  COUNT(*) as count
from tickets
where
  status = :status 
  and DATE(closed_timestamp) = '".date("Y-m-d")."' 
group by assigned_to 
order by count(*) DESC
LIMIT 3

但我想从closed_timestamp表中删除tickets列，并根据datetime表格中的ticket_updates列运行查询

ticketnumber表中的

tickets等于ticketnumber表中的ticket_updates（多行）

因此它应该在没有closed_timestamp列的情况下运行上述查询，并将其基于datetime表中的最新ticket_updates值

示例

在故障单表格中有两行ticketnumber = 1234和5678

ticket_updates表中有3行..两行有ticketnumber = 1234，另一行有ticketnumber = 5678

我想显示票证中的所有行status = 'Completed'和上次更新（ticket_updates表）等于当前日期（2014-05-19）

Answer 1

使用join查询，如下所示，

SELECT 
  t.*,
  COUNT(t.*) as count
from tickets as t
LEFT JOIN ticket_updates as tu
ON tu.ticketnumber = t.ticketnumber
where
  t.status = :status 
group by t.assigned_to 
order by count(t.*) DESC
LIMIT 3

Answer 2

试试这个：

SELECT *
FROM tickets t
JOIN (
  SELECT ticketnumber
  FROM ticket_updates
  WHERE DATE(datetime) = CURDATE()
) u
ON t.ticketnumber = u.ticketnumber
WHERE status = 'Completed'

使用PHP从两个mysql表中选择数据

2 个答案: