Question

我有两张桌子：

comments: id, username, autorpost, comment, id_post, time

posts:  id, autorid, autor, date, longitude, latitude, title, text, town, time

现在我想只选择表格帖子的这些行，其中我在cookie $username = $_COOKIE['username'];中保存的用户名具有与表中用户名相同的值。这可能或者我应该添加任何列吗？

Answer 1

"SELECT
    c.id,
    c.username,
    c.autorpost,
    c.comment,
    c.id_post,
    c.time,
    p.id,
    p.autorid,
    p.autor,
    p.date,
    p.longitude,
    p.latitude,
    p.title,p.text,p.town,p.time 
from comments c 
JOIN posts p 
on p.id=c.id_post 
where c.username='".$username."'";

Answer 2

执行此查询以获取存储在cookie中的用户的帖子。

select Post.* from posts as Post
Left Join
comments as Comment on Post.id = Comment.id_post
where
Comment.username = $_COOKIE['username'];

Answer 3

您可以使用以下代码剪切 -

{{1}}

而不是*使用您想要访问的相应颜色

从两个表中选择变量

3 个答案: