我的查询中有错误

Question

我有一点问题：

public function is_present($Idarticle,$email){

$query=" SELECT * FROM envmail WHERE mail_env='$email' AND id_article='$Idarticle' ";

return mysql_query($query,$this->connection);

}

if($alert->is_present($idarticle,$email)){
echo "yes";
}
else echo "no";

mail_env是一个varchar，id_article是一个int。 我一直都是。

Answer 1

将您的代码更改为此。

public function is_present($Idarticle,$email){

$query=" SELECT * FROM envmail WHERE mail_env='$email' AND id_article='$Idarticle' ";

$result = mysql_query($query,$this->connection);

//return mysql_num_rows($result);
// Update as suggested by @Mark
return mysql_num_rows($result) !== 0

}


//if($alert->is_present($idarticle,$email) > 0 ){
// Updated
if($alert->is_present($idarticle,$email)){
echo "yes";
}
else echo "no";

Answer 2

public function is_present($Idarticle,$email){

$query=" SELECT * FROM envmail WHERE mail_env='".$email."' AND id_article='".$Idarticle."' ";

$result = mysql_query($query,$this->connection);

return mysql_num_rows($result);

}


if($alert->is_present($idarticle,$email) > 0 ){
echo "yes";
}
else echo "no";