Question

我有一个从差异表中获取数据的查询

SELECT p.USER_NAME,count(*) as total, pi.UpdatedDate FROM purchase p JOIN purchasedissues pi on pi.PurchaseId=p.PURCHASE_ID WHERE pi.UpdatedDate>DATE_SUB(NOW(), INTERVAL 1 HOUR) AND p.PURCHASE_DATE=CURDATE() AND p.USER_NAME NOT IN (SELECT username from tbl_test_user) GROUP BY p.USER_NAME having count(*)>2

但我收到了错误

#1064 - 您的SQL语法出错;检查手册对应于您的MySQL服务器版本，以便使用正确的语法在'SELECT p.USER_NAME附近，count（*）为总，pi.UpdatedDate FROM 在第1行购买p JOIN pur'

我无法理解。请任何人帮助我提前谢谢

Answer 1

您的查询没问题。该错误表明它位于SELECT p.USER_NAME,...附近。当您执行多个查询而不终止它时，通常会发生这种情况。前，

SELECT * FROM tableName
SELECT p.USER_NAME,count(*) as total, pi.UpdatedDate FROM purchase....

所以要纠正它，只需添加一个分隔符（通常如果不改变，它是分号）来结束你的第一个查询

SELECT * FROM tableName; -- <== this one
SELECT p.USER_NAME,count(*) as total, pi.UpdatedDate FROM purchase....

Answer 2

试试这个查询！不知道它是否有效，因为我没有在我的机器中设置环境，但它可能会给你一个测试它的本质：）

SELECT p.USER_NAME,count(*) as total FROM purchase p JOIN purchasedissues pi on pi.PurchaseId=p.PURCHASE_ID WHERE pi.UpdatedDate>DATE_SUB(NOW(), INTERVAL 1 HOUR) AND p.PURCHASE_DATE=CURDATE() AND p.USER_NAME NOT IN (SELECT username from tbl_test_user) GROUP BY p.USER_NAME  having total > 2

我的mysql查询中的错误

2 个答案: