Question

我试图解决的问题在以下代码中表达：

@Test
public void buffer_shouldZipAllTheThings() throws InterruptedException {
    final CountDownLatch latch = new CountDownLatch(1);

    Observable<List<String>> strings = Observable.from(Arrays.asList("red", "blue", "yellow", "green")).buffer(3);
    Observable<List<Integer>> integers = Observable.from(Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11)).buffer(3);

    class Zipped {
        final List<String> strings;
        final List<Integer> integers;

        Zipped(List<String> strings, List<Integer> integers) {
            this.strings = strings;
            this.integers = integers;
        }

        @Override public String toString() {
            return "Strings: { " + strings.toString() + " }\n" + "Integers: { " + integers.toString() + " }";
        }
    }

    Observable<Zipped> zipper = Observable.zip(strings, integers, new Func2<List<String>, List<Integer>, Zipped>() {
        @Override public Zipped call(List<String> strings, List<Integer> integers) {
            return new Zipped(strings, integers);
        }
    });

    zipper.subscribeOn(Schedulers.newThread()).subscribe(new Subscriber<Zipped>() {
        @Override public void onCompleted() {
            latch.countDown();
        }

        @Override public void onError(Throwable throwable) {

        }

        @Override public void onNext(Zipped zipped) {
            System.out.println("-- New zipped object: ");
            System.out.println(zipped.toString());
        }
    });

    latch.await();
}

以下是此测试的输出：

-- New zipped object: 
Strings: { [red, blue, yellow] }
Integers: { [1, 2, 3] }
-- New zipped object: 
Strings: { [green] }
Integers: { [4, 5, 6] }

这是所需输出：

-- New zipped object: 
Strings: { [red, blue, yellow] }
Integers: { [1, 2, 3] }
-- New zipped object: 
Strings: { [green] }
Integers: { [4, 5, 6] }
-- New zipped object: 
Strings: { [] }
Integers: { [7, 8, 9] }
-- New zipped object: 
Strings: { [] }
Integers: { [10, 11] }

Answer 1

如何创建无限Observable并使用takeWhile来停止流式传输？

public static void main(String[] args) throws InterruptedException {
    final CountDownLatch latch = new CountDownLatch(1);

    Observable<List<String>> strings = Observable.from(Arrays.asList("red", "blue", "yellow", "green")).buffer(3);
    Observable<List<Integer>> integers = Observable.from(Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11)).buffer(3);

    Observable<List<String>> infiniteStrings = Observable.concat(strings, Observable.<List<String>>from(new ArrayList<String>()).repeat(Schedulers.newThread()));
    Observable<List<Integer>> infiniteIntegers = Observable.concat(integers, Observable.<List<Integer>>from(new ArrayList<Integer>()).repeat(Schedulers.newThread()));

    class Zipped {
        final List<String> strings;
        final List<Integer> integers;

        Zipped(List<String> strings, List<Integer> integers) {
            this.strings = strings;
            this.integers = integers;
        }

        @Override
        public String toString() {
            return "Strings: { " + strings.toString() + " }\n" + "Integers: { " + integers.toString() + " }";
        }
    }

    Observable<Zipped> zipper = Observable.zip(infiniteStrings, infiniteIntegers, new Func2<List<String>, List<Integer>, Zipped>() {
        @Override
        public Zipped call(List<String> strings, List<Integer> integers) {
            System.out.println(strings + " " + integers);
            return new Zipped(strings, integers);
        }
    }).takeWhile(new Func1<Zipped, Boolean>() {

        @Override
        public Boolean call(Zipped zipped) {
            System.out.println(!zipped.strings.isEmpty() || !zipped.integers.isEmpty());
            return !zipped.strings.isEmpty() || !zipped.integers.isEmpty();
        }
    });

    zipper.subscribeOn(Schedulers.newThread()).subscribe(new Subscriber<Zipped>() {
        @Override
        public void onCompleted() {
            System.out.println("Finish");
            latch.countDown();
        }

        @Override
        public void onError(Throwable e) {
            e.printStackTrace();
            latch.countDown();
        }

        @Override
        public void onNext(Zipped zipped) {
            System.out.println("-- New zipped object: ");
            System.out.println(zipped.toString());
        }
    });

    latch.await();
}

Rx Zip缓冲长度不均匀的可观察量

1 个答案: