Question

如何使用rx Java一次压缩多个不同类型的observable？

Observable<Action> actionStream = getAction();
Observable<UserInfo> ownerStream = getOwner();
Observable<List<UserInfo>> relatedUsersStream = getUsers();
Observable<Double> score = getScore();

//Question: how to merge all relusts at once nad call `getResult`?
getResult(action, owner, relatedUsers, score);

更新：找到解决方案。但问题是getResult返回Observable<Result>而不是Result，而zip方法不想编译。

Observable.<Action, UserInfo, List<UserInfo>, Double, Result>zip(
  (action, owner, relatedUsers, score) -> getResult(action, owner, relatedUsers, score)
);

Answer 1

rxjava-joins项目http://mvnrepository.com/artifact/io.reactivex/rxjava-joins/0.22.0包含和/ then / when功能。你可以做这样的事情：

  @Test
  public void rxJoins() throws Exception {

    Observable<Integer> ints = Observable.just(1, 2, 3);
    Observable<String> strs = Observable.just("a", "b", "c");
    Observable<Boolean> bools = Observable.just(false, false, true);

    Plan0<Data> threeItems = JoinObservable.from(ints).and(strs).and(bools).then(Data::new);
    JoinObservable.when(threeItems).toObservable().toBlocking().subscribe(System.out::println);
 }

 private static class Data {
    private final int val1;
    private final String val2;
    private final boolean val3;

    public Data(int val1, String val2, boolean val3) {
        this.val1 = val1;
        this.val2 = val2;
        this.val3 = val3;
    }

    @Override
    public String toString() {
        return "Data{" +
                "val1=" + val1 +
                ", val2='" + val2 + '\'' +
                ", val3=" + val3 +
                '}';
    }
}

此处有更多信息：http://www.introtorx.com/content/v1.0.10621.0/12_CombiningSequences.html

压缩不同类型的多个可观察量

1 个答案: