我正在尝试使用JQuery使用文章中存在的图像创建动态页眉。我打算给图像一个类(.thumbnail)。我想在将文章用于标题后从文章中删除该图像。这是逻辑:
我需要知道如何查找和复制IMG .thumbnail。我确信在我继续解决这个问题时会出现更多问题,但我完全陷入困境。我在想这个错吗?有没有办法在页面上放置相同的图像两次?
感谢您的帮助。
-Alex
编辑:我正在发布解决方案,因为我在我的网站上使用它来解决可能遇到此问题的任何其他人。从答案中取出代码并调整它以使其正常运行。
//need to clone before removing class so that the original is deletable later.
var cache = $('img.thumbnail').clone().removeClass('thumbnail').addClass('Image1').css('float','left');
//remove the original from the text
$('img.thumbnail').remove();
//attach the cloned image to the header
$('#dynHeader').append(cache);
//find the ratio
var ratio = (cache.width() / cache.height());
//set variable to hold image height
var imageHeight = (365);
//set variable to hold image width
var imageWidth = (imageHeight*ratio);
//set the image height & width
cache.height(imageHeight).width(imageWidth);
//figure the amount of width remaining in the header
var remainWidth = $('#dynHeader').width() - imageWidth;
//clone the header image
var dupe = cache.clone();
//work with the cloned image - change the class to Image2, set the width and height dupe.removeClass('Image1').addClass('Image2').css("width",remainWidth+"px").css("height","auto");
//place Image2 to the right of Image1
cache.after(dupe);
然后我使用了一些CSS来定位Image2并隐藏溢出(我正在拍摄的缩放和裁剪效果)。
#dynHeader{
height: 365px;
overflow: hidden;
margin-bottom: 30px;
}
img.Image2{
position: relative;
top: -150px;
}
希望这有助于其他人!感谢Alex以正确的方式指出这一点。
答案 0 :(得分:4)
这应该让你开始:(请记住我的头顶100%的折扣,在这里晚了...可能会有一些拼写错误!)
//Find IMG tag with .thumbnail class:
$('img.thumbnail')
//Move that image to a new DIV (#dynHeader), class it .Image1
// change class before and then grab image
var cache = $('img.thumbnail').removeClass('thumbnail').addClass('Image1').clone();
// remove from context
$('img.thumbnail').remove();
// add it to the div
$('#dynHeader').append(cache);
// Scale the image to x pixels in height, maintain aspect for width
// cache selector
var cache = $('.Image1');
// calculate aspect
var ratio = (cache.width() / cache.height());
// calculate & store width
var remainWidth = (x*ratio);
// scale to x pixels in height
cache.height(x).width(remainWidth);
// Calculate the remaining width of #dynHeader
var remainHeaderWidth = $('#dynHeader').width() - remainWidth;
// Duplicate the IMG to the right of .Image1, call it .Image2
// assuming you mean "duplicate it and add to the right"
var dupe = cache.clone();
dupe.removeClass('Image1).addClass('Image2');
// Set its width to the value of remainWidth
dupe.width(remainHeaderWidth);
// Crop it to the height of .Image1
// not sure about the cropping, here's how you would change it without maintaing aspect
dupe.height(cache.height());
// add it after the first image
cache.after(dupe);
// Position it on the Y axis with a specific value
// cant remember off the top of my head but as far as I know you have to first find its
// position on the axis and then shift it maybe applying relative css positioning
它肯定可以改进,但应该给你一般的想法:)
哦,只要在页面上放置相同的图像,没问题,只需克隆()元素并将其添加到您想要的任意次数!