查询以查找重复和重复的值

Question

 select (a.rowindx) rowindx, (b.rowindx) rowindx1 
 from dedupinitial a,
     dedupinitial b 
 where a.rowindx < b.rowindx 
 and a.poivalue = b.poivalue 
 order by a.rowindx;

此查询为我提供了

之类的结果

rowindx rowindx1 
945 88715
945 91674
945 90947
945 91013
88715   91674
88715   90947
88715   91013

但我想要的结果如下：

rowindx rowindx1 

    945 88715
    945 91674
    945 90947
    945 91013

这是什么问题？

Answer 1

您只需要一分钟（第一列）和一个分组（第二列）

select min(a.rowindx)rowindx, b.rowindx rowindx1 
from dedupinitial a,
dedupinitial b 
where a.rowindx < b.rowindx --and a.rowindx 
 and a.poivalue = b.poivalue 
group by b.rowindx
order by 1;

PS：我不理解和a.rowindx 部分