Question

我有一个银行帐户系统，需要循环浏览帐户中的交易，并在某个日期之前删除任何我有工作职能的日期：

void TransactionList::deleteTransactionsUpToDate(const Date d) {
ostringstream os;
TransactionList tempTrList(*this);
TransactionList trlRecent;

cout << "\n This is everything in the list \n" << tempTrList.toFormattedString();

List<Transaction> tempList = listOfTransactions_;

while (tempTrList.size() > 0 )
{   
    if (tempList.first().getDate() <d)
    {
        listOfTransactions_.deleteOne(tempTrList.newestTransaction());
        tempTrList.deleteGivenTransaction(tempList.first());        
    }
    else
    {
        trlRecent.addNewTransaction(tempTrList.newestTransaction());
    }
    Transaction tr = tempTrList.newestTransaction();

    tempList.deleteOne(tr);
    tempTrList.deleteFirstTransaction();

}

trlRecent.putDataInStream(os,trlRecent);


cout <<  "Non Deltete files" <<trlRecent.toFormattedString(); 
}

但是我需要使用递归。我试图这样做，并且递归过程似乎与循环完全相同，但是它最后一次出现Debug错误，我无法理解为什么。

我的递归函数代码是：

void TransactionList::deleteTransactionsUpToDate
(const Date d, TransactionList trlRecent, TransactionList
tempTrList,List<Transaction> tempList)

{
ostringstream os;
if (tempTrList.size() == 0)
{
    tempTrList = (*this);
    tempList = listOfTransactions_;
cout << "\n This is everything in the list \n"<<tempTrList.toFormattedString();
}
if (tempTrList.size() > 0 )
{   
    if (tempList.first().getDate() <d)
    {
        listOfTransactions_.deleteOne(tempTrList.newestTransaction());
        tempTrList.deleteGivenTransaction(tempList.first());
        //cout << tempTrList.size();
    }
    else
    {
        trlRecent.addNewTransaction(tempTrList.newestTransaction());
    }
    //Transaction tr = ;

    //cout << tempTrList.toFormattedString() << "\n\n";

        /*cout << "test";*/
        tempList.deleteOne(tempTrList.newestTransaction());
        tempTrList.deleteFirstTransaction();
        deleteTransactionsUpToDate(d, trlRecent, tempTrList, tempList);

}
if (trlRecent.size() >0)
trlRecent.putDataInStream(os,trlRecent);

cout <<  "Non Delteted files" <<trlRecent.toFormattedString();
}

如果有人可以提供建议，那将非常感谢。（抱歉，对于文本字段，格式不是很好的行太长了。）

递归和调试错误r6010

0 个答案: