我想问一下mysql查询
我有像这样的表数据
我的数据
`userid | time| date
609 | 07:56:31|2014-01-23
609 | 21:20:47|2014-01-23
609 | 17:25:27|2014-01-24
609 | 17:25:29|2014-01-24
609 | 17:13:54|2014-01-27
609 | 17:13:56|2014-01-27
609 | 07:55:09|2014-01-27`
我尝试了各种方法
但未成功
喜欢
set @start='1900-01-01';
set @finish='2033-12-31';
SELECT data.userid,t.clock_out,data.date from data
inner join (select max(time)as clock_out,date,userid from data where time>='10:01' group by data.userid,tgl)t
on(data.date = t.date and data.userid=t.userid and t.clock_out=date.time)
规则set @start='1900-01-01';
set @finish='2033-12-31';
SELECT data.userid,t.clock_out,data.date from data
inner join (select max(time)as clock_out,date,userid from data where time>='10:01' group by data.userid,tgl)t
on(data.date = t.date and data.userid=t.userid and t.clock_out=date.time)
结果将是
。clock_in where time<='10:00' and clock_out time>'10:00',clock_in or clock_out can fill in the blank/empty,,the date for example 25 and 26 is not input data,but can be retrieved from variable @start='1900-01-01'and @finish='2033-12-31';
userid|date |clock_in | clock_out 609 |2014-01-23 |07:56 |21:20 609 |2014-01-24 | |17:25 609 |2014-01-25 | | 609 |2014-01-26 | | 609 |2014-01-27 |07:55 |17:13
有人可以帮助我...... :(谢谢。提前......
答案 0 :(得分:1)
我认为这就是你想要的,它不完全是你的答案,但我认为这是正确的。
您需要加入该用户ID的所有唯一日期列表,然后使用该列表进行分组,并从中获取min()和max()。
select t1.userid,
t2.date,
min(t1.time) as in_time,
max(t1.time) as out_time
from test t1
join (select distinct date from test where userid = 609) t2
where t1.date = t2.date
and userid = 609
group by t1.userid, t2.date;
我还会说,选择日期部分,而不是日期和时间只是存储日期时间然后分组,这似乎要好得多。
答案 1 :(得分:0)
你试过GROUP_CONCAT吗?
SELECT user_id, date, GROUP_CONCAT(time) as in_out FROM data GROUP BY date ORDER BY date,time;
这不是你需要的100%,但可能足够接近?