Question

我有一个employee表，上面有名字和薪水。

我要打印这两列，其中只包含2条记录，即我的最高薪水和最低薪水的雇员的名字。

它应该看起来像这样：

Name      Salary  
------------------
James       800  
Samanth    3000

以下代码不是我想要的，我希望在2列中使用两个代表每个值的名称的最小值和最大值

SELECT 
    name, MIN(salary), MAX(salary)
FROM
    employee

Answer 1

最佳方法取决于数据库，但是以下方法使用标准SQL：

select max(case when seqnum_asc = 1 then salary end) as min_salary,
       max(case when seqnum_asc = 1 then name end) as min_salary_name,
       max(case when seqnum_desc = 1 then salary end) as max_salary,
       max(case when seqnum_desc = 1 then name end) as max_salary_name      
from (select e.*,
             row_number() over (order by salary asc) as seqnum_asc,
             row_number() over (order by salary desc) as seqnum_desc
      from employee e
     ) e;

Answer 2

您可以通过多种方式执行此操作。这只是其中之一。如果他们的最低/最高薪水相同，它可能会给出多于2条记录

声明@min int，@max int 从YourTable中选择@ min = min（Salary），@ max = max（Salary）

选择名称，从YourTable中获得薪水，其中Salary = @ min或Salary = @ max

Answer 3

我用这种方式。你可以这样

DECLARE @minsalary varchar(60)
set @minsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select min(salary) from employee) 
)

DECLARE @maxsalary varchar(60)
set @maxsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select max(salary) from employee) 
)

select concat(@maxsalary, ' ', @minsalary)

Answer 4

如果使用的是mysql，则可以执行以下操作

按工资第一组分组所有用户
使用“按限制1排序”的最低薪水用户列表
执行第2步以获取最高薪金
联合他们

即使超过1人的最高/最低薪水也可以解决此问题

SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'minimum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary limit 1)tmp 
UNION ALL 
SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'maximum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary DESC limit 1
    )tmp1

样本输出

names       salary  remarks
tom,jolly   10      minimum
sally     10001   maximum

Answer 5

我终于找到了我想要的简单代码。

select emp_name, salary
from employees
where salary = (select max(salary) from employees)
union all
select emp_name, salary
from employees
where salary = (select min(salary) from employees);

我不知道Union。谢谢大家的贡献

Answer 6

您可以通过使用子查询来做到这一点：

SELECT first_name, salary FROM employees
WHERE salary IN ((SELECT MAX (salary) FROM employees), (SELECT MIN (salary) FROM employees))

Answer 7

您可以尝试一下。示例输出。

name      MAX(salary)   MIN(salary)
George    9200          9200
James     5000           100
Kanye     3200          3200
Nicole    4500          4500
Samanth   3000          2300
Umut      1500           250
Vladimir  2300           330

示例表格值

id  name      salary
 1  James        800
 2  Samanth     3000
 3  Umut        1500
 4  Umut         250
 5  Nicole      4500
 6  George      9200
 7  Kanye       3200
 8  Vladimir    2300
 9  Vladimir    1000
10  Vladimir     330
11  James       5000
12  James        100
13  Samanth     2300

SELECT name, MAX(salary), MIN(salary) FROM employee GROUP BY name;

SQL：在一列中获取最小值和最大值

7 个答案: