Question

以下是我正在使用的（部分）结构;它们位于.h文件中：

struct rss_s {
    Radio_types device_type;    // Its device_type which is defined by the typedef above Radio_Types
    char * device_info;      // some thing about the radio NAV/COM/etc.
    char * device_model;     // the Manufactures part/model number.
    char * device_serial;    // the device's serial number..
    int power_48v;           // power to the unit..
    int power_400hz;
    int panel_lamps;         // turn off or on the Panel Lamps only
    void * radio_info;
};

typedef struct tuner_s {    // when we talk about 'sub-radios' we are really saying how many tuners are there??
    char * device_name;    // OS-name
    int frequency[tuned];
    int power;
    int dial_lamp;
    int fd[ ];      // file descriptors
}tuner;

//// 614L8 ::= C614L8

typedef enum Lp_Sw_614L8 { OFF_loop, LEFT, RIGHT, SLEW_LEFT, SLEW_RIGHT } loopsw_614L8;
typedef enum Mo_Sw_614L8 { OFF_614L8, ADF, ANT, LOOP } modesw_614L8;

struct radio_s_614L8 {
    loopsw_614L8 loop_sw_614L8;
    modesw_614L8 mode_sw_614l8;
    int sw_band;
    int sw_bfo;
    int meter;
    tuner * Tuner;
    int tuners;
};

现在归档main.c，其中包含所有常规包含：

// Radio 614L8<br>

static struct radio_s_614L8 radio_614L8 = { { .Tuner = tuner_614L8, .tuners = DIM( tuner_C_614L8 ) } };
static tuner tuner_614L8 = { { .device_name = "/dev/TBD", }  };

static struct rss_s radios[] = {
    { C614L8, "ADF", "614L8", "8384", & radio_C_614L8,},};

// now comes the normal main()

我遇到的错误：

错误：字段名称不在记录或联合初始化程序中

错误:(接近初始化'radio_614L8.loop_sw_614L8'）

错误：'tuner_614L8'未声明此处（不在函数中）

错误：字段名称不在记录或联合初始化程序中

错误:(接近初始化'radio_614L8.loop_sw_614L8'）

错误：'tuner_C_614L8'未声明在这里（不在函数中）

错误：字段名称不在记录或联合初始化程序中

错误:(接近初始化for'tuner_614L8.device_name'）

错误：'radio_C_614L8'未声明此处（不在函数中）

Answer 1

您目前有：

static struct radio_s_614L8 radio_614L8 = { { .Tuner = tuner_614L8, .tuners = DIM( tuner_C_614L8 ) } };
static tuner tuner_614L8 = { { .device_name = "/dev/TBD", }  };

你需要：

static tuner tuner_614L8 =  { .device_name = "/dev/TBD", };
static struct radio_s_614L8 radio_614L8 = { .Tuner = &tuner_614L8, .tuners = 1 };

在您定义或声明之前，您无法引用tuner_614L8之类的变量。您也不应该尝试将非数组转换为数组。您也需要获取调谐器的地址。您没有显示DIM，但我认为它或多或少是这两个等效宏中的一个：

#define DIM(x)  (sizeof(x)/sizeof(*(x)))
#define DIM(x)  (sizeof(x)/sizeof((x)[0]))

进一步分析，您的tuner结构包含一个灵活的数组成员。你不能明智地将这些变量分配为静态或全局变量，或者作为自动变量;你必须用malloc()和亲戚分配它们才能获得非空数组。

然而，考虑到这一点，本代码编译：

typedef enum Radio_types { C614L8 } Radio_types;
enum { tuned = 5 };

typedef struct tuner_s
{
    char *device_name;
    int frequency[tuned];
    int power;
    int dial_lamp;
    int fd[];
} tuner;

typedef enum Lp_Sw_614L8 { OFF_loop, LEFT, RIGHT, SLEW_LEFT, SLEW_RIGHT } loopsw_614L8;
typedef enum Mo_Sw_614L8 { OFF_614L8, ADF, ANT, LOOP } modesw_614L8;

struct radio_s_614L8
{
    loopsw_614L8 loop_sw_614L8;
    modesw_614L8 mode_sw_614l8;
    int sw_band;
    int sw_bfo;
    int meter;
    tuner *Tuner;
    int tuners;
};

static tuner tuner_614L8 = { .device_name = "/dev/TBD", };
static struct radio_s_614L8 radio_614L8 = { .Tuner = &tuner_614L8, .tuners = 1 };

struct rss_s
{
    Radio_types device_type;
    char *device_info;
    char *device_model;
    char *device_serial;
    int power_48v;
    int power_400hz;
    int panel_lamps;
    void *radio_info;
};

struct rss_s radios[] =
{
    { C614L8, "ADF", "614L8", "8384", 0, 0, 0, &radio_614L8, },
};

初始化结构的问题

1 个答案: