Question

我有以下工作查询，它总结了每个月的长度列数/值。

SELECT SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 1 THEN (tblcm.Lgth) ELSE 0 END) AS 'Jan',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 2 THEN (tblcm.Lgth) ELSE 0 END) AS 'Feb',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 3 THEN (tblcm.Lgth) ELSE 0 END) AS 'Mar',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 4 THEN (tblcm.Lgth) ELSE 0 END) AS 'Apr',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 5 THEN (tblcm.Lgth) ELSE 0 END) AS 'May',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 6 THEN (tblcm.Lgth) ELSE 0 END) AS 'Jun',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 7 THEN (tblcm.Lgth) ELSE 0 END) AS 'Jul',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 8 THEN (tblcm.Lgth) ELSE 0 END) AS 'Aug',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 9 THEN (tblcm.Lgth) ELSE 0 END) AS 'Sep',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 10 THEN (tblcm.Lgth) ELSE 0 END) AS 'Oct',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 11 THEN (tblcm.Lgth) ELSE 0 END) AS 'Nov',
   SUM(CASE WHEN DATE_FORMAT(tblcm.omActCompDate, '%m') = 12 THEN (tblcm.Lgth) ELSE 0 END) AS 'Dec',
   SUM(tblcm.Lgth) AS Total

给我以下内容：

Jan 13050
Feb 5200
Mar 48450
Apr 34041
May 38000
Jun 0
Jul 0
Aug 0
Sep 0
Oct 0
Nov 0
Dec 0

如何只获得大于零的AVG？

我试过：avg（nullif（tblcm.Lgth，0））为m_Avg但得到1825
我也试过：avg（tblcm.Lgth = 0的情况，然后是null，否则tblcm.Lgth结束）作为m_Avg但也得到1825
我需要得到27748（这是1月至5月的总和，除以5个月）

Answer 1

我很确定你需要一个子查询才能做到这一点。以下假设您的原始查询正确，因为已发布并按您所说的方式运行。这是未经测试的，你可能在你的问题中包含了更多细节，所以如果这不符合你的需要，现在就告诉我。

SELECT AVG(sumLgth) AS avgLgth, SUM(sumLgth) AS totalLgth,
    SUM(CASE WHEN theMonth = 1 THEN (tbl.sumLgth) ELSE 0 END) AS 'Jan',
    SUM(CASE WHEN theMonth = 2 THEN (tbl.sumLgth) ELSE 0 END) AS 'Feb',
    ...
FROM (
    SELECT MONTH(omActCompDate) AS theMonth, SUM(lgth) AS sumLgth
    FROM tblcm
    GROUP BY MONTH(omActCompDate)
    HAVING sumLgth > 0
) tbl

使用/零计算每月的平均值（不包括月份）

1 个答案: