Question

我有一个像这样的json字符串

"{
  "RSS": {
    "Channel": {
      "item": [
        {
          "title": "Overlay HD/CC",
          "guid": "1",
          "description": "This example shows tooltip overlays for captions and quality.",
          "jwplayer:image": "http://content.jwplatform.com/thumbs/3XnJSIm4-640.jpg",
          "jwplayer:source": [
            {
              "@file": "http://content.jwplatform.com/videos/3XnJSIm4-DZ7jSYgM.mp4",
              "@label": "720p"
            },
            {
              "@file": "http://content.jwplatform.com/videos/3XnJSIm4-kNspJqnJ.mp4",
              "@label": "360p"
            },
            {
              "@file": "http://content.jwplatform.com/videos/3XnJSIm4-injeKYZS.mp4",
              "@label": "180p"
            }
          ],
          "jwplayer:track": [
            {
              "@file": "http://content.jwplatform.com/captions/2UEDrDhv.txt",
              "@label": "English"
            },
            {
              "@file": "http://content.jwplatform.com/captions/6aaGiPcs.txt",
              "@label": "Japanese"
            },
            {
              "@file": "http://content.jwplatform.com/captions/2nxzdRca.txt",
              "@label": "Russian"
            },
            {
              "@file": "http://content.jwplatform.com/captions/BMjSl0KC.txt",
              "@label": "Spanish"
            }
          ]
        }
      ]
    },
    "@xmlns:jwplayer": "http://support.jwplayer.com/customer/portal/articles/1403635-media-format-reference#feeds",
    "@version": "2.0"
  }
}"

我尝试使用json.net将其转换为xmlDocument：

XmlDocument xmlDoc = JsonConvert.DeserializeXmlNode(json);
using (var stringWriter = new StringWriter())
using (var xmlTextWriter = XmlWriter.Create(stringWriter))
{
    xmlDoc.WriteTo(xmlTextWriter); // Exception: Cannot use a prefix with an empty namespace.
    xmlTextWriter.Flush();
    return stringWriter.GetStringBuilder().ToString();
}

但是当我尝试访问OuterXml属性时，它会抛出异常“不能使用带有空命名空间的前缀。”

是否有修复该异常或其他方法将json转换为xml字符串？ xml字符串的名称空间如下所示

<jwplayer:image>http://content.jwplatform.com/thumbs/3XnJSIm4-640.jpg</jwplayer:image>

Answer 1

我不确定为什么你的代码抛出异常，因为它必须是一个有效的XML，因为XML已成功加载到XmlDocument对象。

我可以想到获取格式化XML字符串的另一种方法是使用从XmlDocument.OuterXml加载未格式化的XML字符串到XDocument，然后将其转换为格式化的XML字符串：

XmlDocument xmlDoc = JsonConvert.DeserializeXmlNode(json);
XDocument xDoc = XDocument.Parse(xmlDoc.OuterXml);
return xDoc.ToString();

效率不高，但这种方法很简单且有效。

使用命名空间将Json转换为XML String？

1 个答案: