Question

我有一个像xmlns一样的xml -

  <ChannelInfo xmlns="Vijayabank_43_vijayBank1">
  <RegionName xmlns="Vijayabank_43_vijayBank1_Prime">
    <Width xmlns="Width">768</Width>
    <Height xmlns="Height">614</Height>
    <Top xmlns="Top">100</Top>
    <Left xmlns="Left">20</Left>
    <Audio xmlns="Audio">1</Audio>
  </RegionName>
  <RegionName xmlns="Vijayabank_43_vijayBank1_SubPrime">
    <Width xmlns="Width">452</Width>
    <Height xmlns="Height">614</Height>
    <Top xmlns="Top">100</Top>
    <Left xmlns="Left">808</Left>
    <Audio xmlns="Audio">0</Audio>
  </RegionName>
 <RegionName xmlns="Vijayabank_43_vijayBank1_Banner1">
   <Width xmlns="Width">1240</Width>
   <Height xmlns="Height">54</Height>
   <Top xmlns="Top">714</Top>
   <Left xmlns="Left">20</Left>
   <Audio xmlns="Audio">0</Audio>
 </RegionName>
</ChannelInfo>

我希望将它转换为json，如下所示，在php中使用xmlns -

  "ChannelInfo": {
   "-xmlns": "Vijayabank_43_vijayBank1",
   "RegionName": [
     {
       "-xmlns": "Vijayabank_43_vijayBank1_Prime",
       "Width": {
       "-xmlns": "Width",
       "#text": "768"
     },
       "Height": {
        "-xmlns": "Height",
        "#text": "614"
     },
     "Top": {
       "-xmlns": "Top",
       "#text": "100"
     },
     "Left": {
       "-xmlns": "Left",
       "#text": "20"
     },
     "Audio": {
       "-xmlns": "Audio",
       "#text": "1"
     }
   },
   {
     "-xmlns": "Vijayabank_43_vijayBank1_SubPrime",
     "Width": {
       "-xmlns": "Width",
       "#text": "452"
     },
     "Height": {
      "-xmlns": "Height",
      "#text": "614"
    },
     "Top": {
       "-xmlns": "Top",
       "#text": "100"
     },
     "Left": {
       "-xmlns": "Left",
      "#text": "808"
    },
    "Audio": {
      "-xmlns": "Audio",
       "#text": "0"
     }
   },
   {
    "-xmlns": "Vijayabank_43_vijayBank1_Banner1",
    "Width": {
      "-xmlns": "Width",
      "#text": "1240"
    },
    "Height": {
      "-xmlns": "Height",
      "#text": "54"
    },
    "Top": {
      "-xmlns": "Top",
      "#text": "714"
    },
    "Left": {
      "-xmlns": "Left",
      "#text": "20"
    },
    "Audio": {
      "-xmlns": "Audio",
      "#text": "0"
     }
   }
   ]
   }
   }

我尝试过使用simple_load_string（）它会发出类似命名空间警告的警告：xmlns：URI DailyXml不是绝对的。我想要xmlns属性。

如何解决这个问题？还有其他方法可以实现吗？

Answer 1

目前，您只是将XML序列化为JSON。您需要读取数据并转换为您想要的JSON：

$dom = new DOMDocument();
$dom->loadXml($xml);
$xpath = new DOMXpath($dom);

$channel = $dom->documentElement;
$result = [
  'id' => $channel->namespaceURI,
  'Regions' => []
];
foreach ($xpath->evaluate('*', $channel) as $region) {
  $regionId = $region->namespaceURI;
  $result['Regions'][$regionId] = [];
  foreach ($xpath->evaluate('*', $region) as $property) {
    $result['Regions'][$regionId][$property->namespaceURI] = 
      trim($property->textContent);
  }
}

echo json_encode($result, JSON_PRETTY_PRINT);

输出：https://eval.in/154181

{
    "id": "Vijayabank_43_vijayBank1",
    "Regions": {
        "Vijayabank_43_vijayBank1_Prime": {
            "Width": "768",
            "Height": "614",
            "Top": "100",
            "Left": "20",
            "Audio": "1"
        },
        "Vijayabank_43_vijayBank1_SubPrime": {
            "Width": "452",
            "Height": "614",
            "Top": "100",
            "Left": "808",
            "Audio": "0"
        },
        "Vijayabank_43_vijayBank1_Banner1": {
            "Width": "1240",
            "Height": "54",
            "Top": "714",
            "Left": "20",
            "Audio": "0"
        }
    }
}

XML非常破碎。 xmlns属性定义元素的命名空间。命名空间是元素定义的格式。（如（X）HTML，Atom，...）

在XML中，xmlns的使用方式与＆＃34; id＆＃34;或＆＃34;名称＆＃34; ChannelInfo和RegionName元素的属性。标识文档中元素的东西。

在其他元素节点上，它只是无用的，重复的数据。信息已经在元素名称中。

更好的XML：

<Channel xmlns="http://domain.tld/ns/ads" id="Vijayabank_43_vijayBank1">
  <Region id="Vijayabank_43_vijayBank1_Prime">
    <Width>768</Width>
    <Height>614</Height>
    <Top>100</Top>
    <Left>20</Left>
    <Audio>1</Audio>
  </Region>
  ...
</Channel>

使用xml命名空间将xml转换为php中的json

1 个答案: