我用Java编写了一个Mandelbrot Set Fractal,并且包含了对分形进行平移和放大一定量的功能。唯一的事情是,当我平移图像并尝试放大时,看起来它似乎试图放大中心并平移一点。平移和缩放不是真正平移或缩放更多实际上是重新计算分形,看起来好像是在平移或缩放。
这是我的代码。
package core;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.event.KeyEvent;
import java.awt.event.KeyListener;
import java.awt.image.BufferedImage;
import javax.swing.JFrame;
public class Main extends JFrame implements KeyListener
{
// Constant screen dimensions
private final int SCREEN_WIDTH = 800;
private final int SCREEN_HEIGHT = 600;
// Fractal image
private BufferedImage fractal;
// Number of max iterations
private int maxIter = 500;
// Zoom factor
private double zoom = 150;
// Coordinates
private double xPos = SCREEN_WIDTH / 2;
private double yPos = SCREEN_HEIGHT / 2;
// Algorithm variables
private double zx, zy, cX, cY, tmp;
public static void main(String[] args)
{
// Create the frame and make it visible
new Main().setVisible(true);
}
public Main()
{
super("Mandelbrot Set");
setSize(SCREEN_WIDTH, SCREEN_HEIGHT);
setDefaultCloseOperation(EXIT_ON_CLOSE);
setLocationRelativeTo(null);
addKeyListener(this);
setResizable(false);
// Compute the fractal to start
ComputeFractal();
}
public void ComputeFractal()
{
fractal = new BufferedImage(SCREEN_WIDTH, SCREEN_HEIGHT, BufferedImage.TYPE_INT_RGB);
for (int y = 0; y < fractal.getHeight(); y++)
{
for (int x = 0; x < fractal.getWidth(); x++)
{
zx = zy = 0;
cX = (x - xPos) / zoom;
cY = (y - yPos) / zoom;
int iter;
for (iter = 0; iter < maxIter && zx * zx + zy * zy < 4; iter++)
{
tmp = zx * zx - zy * zy + cX;
zy = 2.0 * zx * zy + cY;
zx = tmp;
}
// If the point is in the set
if (iter == maxIter)
{
Color color = new Color(0, 0, 0);
fractal.setRGB(x, y, color.getRGB());
}
// If the point is not in the set
else
{
double r = iter | (iter << 2);
while (r > 255) { r-=255; }
double g = iter | (iter << 4);
while (g > 255) { g-=255; }
double b = iter | (iter << 8);
while (b > 255) { b-=255; }
Color color = new Color((int) r, (int) g, (int) b);
fractal.setRGB(x, y, color.getRGB());
}
}
}
repaint();
}
public void paint(Graphics g)
{
// Draw the fractal
g.drawImage(fractal, 0, 0, this);
}
public void keyReleased(KeyEvent e)
{
if (e.getKeyCode() == KeyEvent.VK_SPACE)
{
zoom += 100;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_LEFT)
{
xPos += 50;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_RIGHT)
{
xPos -= 50;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_UP)
{
yPos += 50;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_DOWN)
{
yPos -= 50;
ComputeFractal();
}
}
public void keyTyped(KeyEvent e)
{
}
public void keyPressed(KeyEvent e)
{
}
}
任何人都可以告诉我,我可以做些什么来使缩放更精确到用户平移相机的位置?
提前谢谢。
编辑:想知道这个程序将呈现什么的人的图片。
答案 0 :(得分:0)
基本上最新的是,在mandelbrot的中心是xPos 0和yPos 0.你的缩放是xPos和yPos(cX =(x - xPos)/ zoom;)。例如,如果你的xPos是-500并且你增加你的变焦,它将是-500 /变焦,所以它将是 - 4,下次你缩放它将是 - 3,依此类推,直到它达到0。
你想要做的是在x和y上从(-2:2)在mandelbrot上设置一个固定位置(x,y)。因此,该位置将成为您在mandelbrot上渲染图像的中心。缩放将告诉mandelbrod集上每个像素离中心有多远。例如,如果中心像素在mandelbrot上为0,0则基于缩放,中心像素+ 1将为0.1,0或0.00005,0。箭头键将移动固定位置。
cX = xPos/SCREEN_WIDTH + (x - (fractal.getWidth() >> 1)) / zoom;
cY = yPos/SCREEN_HEIGHT + (y - (fractal.getHeight() >> 1)) / zoom;
如果你在代码中粘贴它会起作用,但我建议使用xPos,yPos值大多在范围(-2:2),它会更有意义。另外我建议你改变一下你的方式。为此你需要改变......
private double zoom = 0.01;
private double xPos = 0;
private double yPos = 0;
...
cX = xPos + (x - (fractal.getWidth() >> 1)) * zoom;
cY = yPos + (y - (fractal.getHeight() >> 1)) * zoom;
...
public void keyReleased(KeyEvent e)
{
if (e.getKeyCode() == KeyEvent.VK_SPACE)
{
zoom *= 0.9;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_LEFT)
{
xPos -= 10 * zoom;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_RIGHT)
{
xPos += 10 * zoom;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_UP)
{
yPos -= 10 * zoom;
ComputeFractal();
}
else if (e.getKeyCode() == KeyEvent.VK_DOWN)
{
yPos += 10 * zoom;
ComputeFractal();
}
}
我必须做mandelbrot作为我在大学的作业,所以如果你有兴趣,可以在这里查看here。