Question

如何将电话号码格式化为（###）### - ####至##########？有最好的方法吗？我可以使用String.Substring来获取每个数字块，然后将它们连接起来。但是，还有其他复杂的方法吗？

Answer 1

简单的正则表达式取代怎么样？

string formatted = Regex.Replace(phoneNumberString, "[^0-9]", "");

这基本上只是一个数字的白名单。看到这个小提琴：http://dotnetfiddle.net/ssdWSd

输入：（123）456-7890

输出：1234567890

Answer 2

我是用LINQ做的：

var result = new String(phoneString.Where(x => Char.IsDigit(x)).ToArray());

虽然正则表达式也有效，但这不需要任何特殊设置。

Answer 3

一种简单的方法是：

myString = myString.Replace("(", "");
myString = myString.Replace(")", "");
myString = myString.Replace("-", "");

用空字符串替换每个字符。

Answer 4

试试这个：

resultString = Regex.Replace(subjectString, @"^\((\d+)\)(\d+)-(\d+)$", "$1$2$3");

REGEX EXPLANATION

^\((\d+)\)(\d+)-(\d+)$

Assert position at the beginning of the string «^»
Match the character “(” literally «\(»
Match the regex below and capture its match into backreference number 1 «(\d+)»
   Match a single character that is a “digit” (0–9 in any Unicode script) «\d+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “)” literally «\)»
Match the regex below and capture its match into backreference number 2 «(\d+)»
   Match a single character that is a “digit” (0–9 in any Unicode script) «\d+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “-” literally «-»
Match the regex below and capture its match into backreference number 3 «(\d+)»
   Match a single character that is a “digit” (0–9 in any Unicode script) «\d+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Assert position at the end of the string, or before the line break at the end of the string, if any (line feed) «$»

$1$2$3

Insert the text that was last matched by capturing group number 1 «$1»
Insert the text that was last matched by capturing group number 2 «$2»
Insert the text that was last matched by capturing group number 3 «$3»

格式化电话号码

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