Question

我试图找到一种在同步函数调用中使用异步XMPP库的方法。

我想编写一个简单的Python函数，通过XMPP消息发送其参数，接收回复，并返回此回复：

def read_ans(a,b,c):
    # send [a,b,c] via an XMPP message
    # wait for XMPP message with reply, z
    return z

我找到了sleekxmpp库，并编写了一个简单的脚本来执行此操作。我遇到的问题是sleekxmpp在多个线程中运行，并为接收的消息指定回调。我不确定如何同步运行它。

到目前为止我的内容如下。如何将self.last_message传递给read_ans以便可以返回？

谢谢！

import sleekxmpp
class XMPP(sleekxmpp.ClientXMPP):

    def __init__(self, jid, password, myargs):
        sleekxmpp.ClientXMPP.__init__(self, jid, password)
        self.add_event_handler("session_start", self.start)

        # Store arguments
        self.myargs = myargs

        # This is where we store the last message received
        self.last_message = ""
        self.add_event_handler("message", self.message)

    def start(self, event):
        self.send_presence()
        self.get_roster()

        self.send_message(mto=recipient, mbody=str(self.myargs))

    def message(self, msg):
        if msg['type'] in ('chat', 'normal'):
            #Store the received message
            self.last_message = msg['body']
            self.disconnect()

def read_ans(a,b,c):
    xmpp = XMPP("user", "pass", [a,b,c])            
    if xmpp.connect():
        xmpp.process(block=True)

    # How can I return the message here?
    return '!?!?'

if __name__ == '__main__':
    read_ans(1,2,3)

如何在sleekxmpp的同步代码中使用XMPP？

0 个答案: