Question

使用下表和数据

CREATE TABLE [dbo].[AccountStatus](
[Id] [INT] NOT NULL,
[AccountId] [VARCHAR](15) NOT NULL,
[Status] [VARCHAR](15) NOT NULL,
[DateChanged] [DATETIME] NOT NULL
)

INSERT AccountStatus (Id,AccountId,Status,DateChanged) VALUES (1 , 'A', 'Imported', '1/1/2014')
INSERT AccountStatus (Id,AccountId,Status,DateChanged) VALUES (1 , 'A', 'Validated', '1/12/2014')
INSERT AccountStatus (Id,AccountId,Status,DateChanged) VALUES (1 , 'A', 'Contacted', '1/21/2014')
INSERT AccountStatus (Id,AccountId,Status,DateChanged) VALUES (1 , 'A', 'Qualified', '2/1/2014')
INSERT AccountStatus (Id,AccountId,Status,DateChanged) VALUES (1 , 'A', 'Closed', '2/10/2014')

如何使用tql创建输出，显示给定帐户处于状态的持续时间？

值是不可变的，永远不会更新。

我正在寻找

Status | Start | End | Duration

我有一个真正的大脑冻结。

由于

Answer 1

如果我已正确理解您的问题，我会使用以下方法。请注意，代码未经过测试，因为您没有提供数据（我编写代码＆＃34;在空中＆＃34;）。如果你发布DDL＆amp; amp;会让你的答案变得简单得多。数据与您的问题。

--  First sequence all Statuses, on a per account basis
;WITH StatusSeq AS
(
    SELECT   Id 
            ,Seq    = ROW_NUMBER() OVER (PARTITION BY AccountID ORDER BY DateChanged)
            ,AccountId
            ,[Status]
            ,DateChanged
    FROM dbo.AccountStatus
)
--  Second: Join the table to itself, so that on the right hand side
--          of the current row, you read the Status tha immediately followed
SELECT   T1.AccountID
        ,T1.[Status]
        ,StartDT    = T1.DateChanged
        ,EndDT      = T2.DateChanged
        --  I've chosen to show the date difference as days here, 
        --  you may want to choose something else
        ,Duration   = DATEDIFF(DAY, T1.DateChanged, T2.DateChanged)
FROM StatusSeq  T1
JOIN StatusSeq  T2  ON T1.Seq = T2.Seq - 1

Answer 2

假设开始和结束有一行：

SELECT Status,
  MIN(DateChanged) AS [Start],
  MAX(DateChanged) AS [End],
  MAX(DateChanged) - MIN(DateChanged) AS [Duration]
FROM AccountStatus
GROUP BY Status

您必须使用Duration

使用CONVERT

如何编写TSQL来计算持续时间

2 个答案: