Question

我在删除名称/ ID在我的NSMutableArray中的所有节点时遇到了一些麻烦。我已将每个对象的值设置为唯一名称。所以我只能删除NSMutableArray中的那些。

对象是在循环中创建的，每个对象的名称都是唯一的。

像这样：

    myObject.name = @"8dAN3kgh6E";

下一个循环

    myObject.name = @"WsFkdGrmHm";

下一个循环

    myObject.name = @"ov5BjzHGiw";

然后添加这些值并将其存储在数组中。

NSMutableArray * currentShapeArray

(
    8dAN3kgh6E,
    WsFkdGrmHm,
    ov5BjzHGiw
)

然后我遍历currentShapeArray，我喜欢这样：

for (NSString *myObjectNames in currentShapeArray) {

      NSLog(@"%@", myObjectNames); //works and gives each value correctly
}

但是对于我的生活，我似乎无法弄清楚如何删除包含那个specfic node.name的对象。

与[myObject removeFromParent]类似; ...但我需要根据myObject.name属性进行选择。

我确信这很简单，希望有人可以给我一个正确方向的推动。谢谢！

更新：1。

我尝试过sangony的建议，出于某种原因，当我使用它时，它会给我以下错误。

2014-05-07 23:11:56.163 dotmatcher[1149:60b] NODE NAME: FY7opRB1Wk
2014-05-07 23:11:56.164 dotmatcher[1149:60b] ButtonTmp 1
2014-05-07 23:11:56.164 dotmatcher[1149:60b] Previous 1
2014-05-07 23:11:56.164 dotmatcher[1149:60b] -[__NSCFString name]: unrecognized selector    sent to instance 0xee1fe50
2014-05-07 23:11:56.167 dotmatcher[1149:60b] *** Terminating app due to uncaught     exception 'NSInvalidArgumentException', reason: '-[__NSCFString name]: unrecognized selector     sent to instance 0xee1fe50'


- (void) touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
for (UITouch *touch in touches) {

UITouch* touch = [touches anyObject];
CGPoint loc = [touch locationInNode:self];
NSArray *nodes = [self nodesAtPoint:loc];

for (SKNode *node in nodes) {

    NSString *tmp = node.name;
    if (tmp.length !=0) {
        NSLog(@"ended");

        NSString *buttonTmp = [node.userData objectForKey:@"buttonType"];

        if ([buttonTmp isEqualToString:@"1"] && [previousButton isEqualToString:@"1"]) {
            endButton = @"1";


            NSLog(@"NODE NAME: %@",node.name);
            NSLog(@"ButtonTmp %@", buttonTmp);
            NSLog(@"Previous %@", previousButton);

            NSMutableArray *discardedItems = [NSMutableArray array];
            for(SKNode *object in currentShapeArray)
            {
                if([object.name isEqualToString:node.name])
                {
                    [object removeFromParent]; // not sure if you need this or not
                    [discardedItems addObject:object];
                }
            }
            [currentShapeArray removeObjectsInArray:discardedItems];


            NSLog(@"ButtonID: %@",[node.userData objectForKey:@"buttonID"]);
            NSLog(@"ButtonType: %@",[node.userData objectForKey:@"buttonType"]);
            NSLog(@"ButtonColumn: %@",[node.userData objectForKey:@"buttonColumn"]);
            NSLog(@"ButtonRow: %@",[node.userData objectForKey:@"buttonRow"]);

            NSLog(@"AFTER REMOVE%@",currentShapeArray);

        }

    }
}
}
}

更新2 这是让它运转的最终代码。谢谢Sangony！

NSMutableArray *discardedItems = [NSMutableArray array];
for(SKNode *object in currentShapeArray)
{
        [object removeFromParent]; 
        [discardedItems addObject:object];

}
[currentShapeArray removeObjectsInArray:discardedItems];

Answer 1

或许这样的事情：

NSMutableArray *discardedItems = [NSMutableArray array];
for(SKNode *object in currentShapeArray)
{
    if([object.name isEqualToString:node.name])
    {
        [object removeFromParent]; // not sure if you need this or not
        [discardedItems addObject:object];
    }
}
[currentShapeArray removeObjectsInArray:discardedItems];

Sprite Kit - 根据NSMutableArray对象列表删除SKNode

1 个答案: