Question

我有这个代码在一个数组中找到3个连续的日期，但我想知道是否有更好的方法来做到这一点？

php代码：

$datesarray = array('2012-10-01', '2012-10-03', '2012-10-04', '2012-10-05', '2012-10-08', '2012-10-09');

    $count = 0;
    $result = "Nothing found";

        foreach ($datesarray as $value) {
            if(strtotime($datesarray[$count]) - strtotime($datesarray[$count-1]) - strtotime($datesarray[$count-2]) == -1349150400) {
                $result = "3 Consecutive dates found";
            }
        $count++; 
        }  

    echo "Result: $result";

Answer 1

你的脚本给了我：

Result: Nothing found

但有3个连续日期

我改变了剧本：

<?php

$datesarray = array('2012-10-01', '2012-10-03', '2012-10-04', '2012-10-05', '2012-10-08', '2012-10-09');

$result = "Nothing found";


$diff = strtotime('2014-05-07') - strtotime('2014-05-06');

for ($i=2, $c=count($datesarray); $i<$c; ++$i) {
    if (strtotime($datesarray[$i-1]) - strtotime($datesarray[$i-2]) == $diff &&
        strtotime($datesarray[$i]) - strtotime($datesarray[$i-2]) == $diff * 2) {
            $result = "3 Consecutive dates found";                
            break;
    }

}
echo "Result: $result";

，结果是

Result: 3 Consecutive dates found

这是你所期望的吗？

php在数组中找到3个连续日期

1 个答案: