Question

我在matlab中读取dxf文件并获得此结构。如何保护名称与图层名称相同的separeted矩阵中的所有坐标。我的意思是

基准面1 = [   10.8031269501964,2.06417715317460,5,3.70163846035642,2.06417715317460,5; ...]

数据

行= {[10.8031269501964,2.06417715317460,5,3.70163846035642,2.06417715317460,5]， '基准面1'; [3.70163846035642,2.06417715317460,5,3.70163846035642,2.06417715317460,0]， '基准面1'; [3.70163846035642,2.06417715317460,0,10.8031269501964 ，2.06417715317460,0]， '基准面1'; [10.8031269501964,7.75770563520633,5,10.8031269501964,7.75770563520633,0]， 'Plane4'; [10.8031269501964,2.06417715317460,5,10.8031269501964,2.06417715317460,0]， '基准面1'; [3.70163846035642,7.75770563520633 ，5,10.8031269501964,7.75770563520633,5]， 'Plane4'; [10.8031269501964,7.75770563520633,0,3.70163846035642,7.75770563520633,0]， 'Plane4'; [3.70163846035642,7.75770563520633,5,3.70163846035642,7.75770563520633,0]， 'Plane4'; [10.8031269501964,7.75770563520633,5,10.8031269501964,7.75770563520633,0]， 'Plane3'; [10.8031269501964,2.06417715317460,5,10.8031269501964,2.06417715317460,0]， '基准面1'; [3.70163846035642,7.75770563520633,2.50000000000000,3.70163846035642,7.75770563520633,1.14583181629325] 'Plane3'; [3.70163846035642,2.06417715317460,2.50000000000 000,8.19164033348243,2.06417715317460,2.50000000000000]， '基准面1'; [8.19164033348243,2.06417715317460,2.50000000000000,8.19164033348243,2.06417715317460,1.14583181629325]， '基准面1'; [8.19164033348243,2.06417715317460,1.14583181629325,3.70163846035642,2.06417715317460,1.14583181629325]， '基准面1'; [ 3.70163846035642,2.06417715317460,5,3.70163846035642,2.06417715317460,2.50000000000000]， '基准面1'; [3.70163846035642,7.75770563520633,1.14583181629325,3.70163846035642,7.75770563520633,0]， 'Plane3'; [8.19164033348243,7.75770563520633,2.50000000000000,3.70163846035642,7.75770563520633,2.50000000000000]，” Plane3 '; [3.70163846035642,7.75770563520633,5,10.8031269501964,7.75770563520633,5]，' Plane3 '; [10.8031269501964,7.75770563520633,0,3.70163846035642,7.75770563520633,0]，' Plane3' ; [3.70163846035642,7.75770563520633,1.14583181629325,8.19164033348243,7.75770563520633， 1.14583181629325]， 'Plane3'; [8.19164033348243,7.75770563520633,1.14583181629325,8.19164033348243,7.75770563520633,2.50000000000000]， 'Plane3'; [3.70163 846035642,7.75770563520633,5,3.70163846035642,7.75770563520633,2.50000000000000]， 'Plane3'; [10.8031269501964,7.75770563520633,5,10.8031269501964,7.75770563520633,0]， '计划2'; [10.8031269501964,7.75770563520633,5,10.8031269501964,2.06417715317460,5]，”计划2 '; [10.8031269501964,2.06417715317460,0,10.8031269501964,7.75770563520633,0]，' 计划2 '; [10.8031269501964,2.06417715317460,5,10.8031269501964,2.06417715317460,0]，' 计划2' ; [3.70163846035642,7.75770563520633,5,3.70163846035642,2.06417715317460， 5]， 'Plane4'; [3.70163846035642,2.06417715317460,5,3.70163846035642,2.06417715317460,0]， 'Plane4'; [3.70163846035642,2.06417715317460,0,3.70163846035642,7.75770563520633,0]， 'Plane4'; [3.70163846035642,7.75770563520633,0， 3.70163846035642,7.75770563520633,5]， 'Plane4'; [3.70163846035642,2.06417715317460,5,3.70163846035642,7.75770563520633,0]， 'Plane4'; [3.70163846035642,7.75770563520633,5,3.70163846035642,2.06417715317460,0]， 'Plane4'; [3.70163846035642， 4.91094139419046,2.50000000000000,3.70163846035642,4.9109413941904 6,0]， 'Plane4'; [3.70163846035642,4.91094139419046,0,3.70163846035642,2.06417715317460,2.50000000000000]， 'Plane4'; [3.70163846035642,2.06417715317460,2.50000000000000,3.70163846035642,4.91094139419046,5]， 'Plane4'; [3.70163846035642,4.91094139419046， 5,3.70163846035642,7.75770563520633,1.82291590814662]， 'Plane4'; [3.70163846035642,7.75770563520633,1.82291590814662,3.70163846035642,4.91094139419046,0]， 'Plane4'; [10.8031269501964,7.75770563520633,5,8.19164033348243,7.75770563520633,2.50000000000000]， 'Plane3'; [ 8.19164033348243,7.75770563520633,2.50000000000000,8.19164033348243,7.75770563520633,1.14583181629325]， 'Plane3'; [8.19164033348243,7.75770563520633,1.14583181629325,10.8031269501964,7.75770563520633,0]， 'Plane3';}

Answer 1

不使用eval将变量用作名称（这会导致其他问题），您可以考虑将结构拆包到一个可以自动生成的结构中......

VectorLength=6; % length of the vectors in the input
names=unique(Line(:,2));

for ii=1:length(names);
 nameLocations=strcmp(Line(:,2),names{ii});
LineStruct.(names{ii})=...
    reshape([Line{nameLocations,1}],sum(nameLocations),VectorLength);
end

给出了

LineStruct = 

     Plan2: [4x6 double]
    Plane1: [9x6 double]
    Plane3: [12x6 double]
    Plane4: [15x6 double]

可以通过调用结构的字段来使用矩阵，例如LineStruct.Plane1

Answer 2

以下是您一次只能在一架飞机上完成的方法。它当然可以自动化，但是如果你有很多飞机，你可能不会想要这样做：

Plane1 = Line(strcmp(Line(:,2),'Plane1'),1);
Plane1 = vertcat(Plane1{:})

在matlab中安排Cell结构

2 个答案: