Question

我有一个mat数据并提取8个特征这个文件。我应该将这些功能安排为一个单元格，并重复12个类别我想安排和统一这段代码作为一个代码？

feature_mean1=zeros(12,15);
 for vmean1= 1:12
 feature_mean1(vmean1,:)= mean(Catrgoryy1{vmean1});
 end
feature_mean2=zeros(12,15);
 for vmean2= 1:12
 feature_mean2(vmean2,:)= mean(Catrgoryy2{vmean2});
end
%**********************
 %***************
feature_min1=zeros(12,15);
for vmin1= 1:12
feature_min1(vmin1,:)= min(Catrgoryy1{vmin1});
end
feature_min2=zeros(12,15);
for vmin2= 1:12
feature_min2(vmin2,:)= min(Catrgoryy2{vmin2});
end
  %***************
 X=zeros(30,4); 

h=1;
X_1=[feature_mean1(1,:)',feature_std1(1,:)',feature_min1(1,:)',feature_max1(1,:)',feature_mean2(1,:)',feature_std2(1,:)',feature_min2(1,:)',feature_max2(1,:)'];%
Y_1=repmat(1,length(X_1),1);
%%%**************222*************                                       
X_2=[feature_mean1(2,:)',feature_std1(2,:)',feature_min1(2,:)',feature_max1(2,:)',feature_mean2(2,:)',feature_std2(2,:)',feature_min2(2,:)',feature_max2(2,:)'];
Y_2=repmat(2,length(X_2),1);
%%%**************333**************
.
.
.
X_12=[feature_mean1(12,:)',feature_std1(12,:)',feature_min1(12,:)',feature_max1(12,:)',feature_mean2(12,:)',feature_std2(12,:)',feature_min2(12,:)',feature_max2(12,:)'];
Y_12=repmat(12,length(X_12),1);

Answer 1

首先必须为每个功能形成8个数组然后在for循环中插入所有这些

for o=1:12
  Xf(o,:)=[feature_mean11{o},feature_std11{o},feature_min11{o},feature_max11{o},feature_mean22{o},feature_std22{o},feature_min22{o},feature_max22{o}];
end

光洁度

将嵌套单元格排序为一个排列函数

1 个答案: