Question

我有一个上传表单，只能上传六张JPG和PNG格式的图片。

问题是：每当我选择两个GIF图像和四个JPG图像时，它都会上传JPG并拒绝GIF。如何对此进行验证，如果只有一个GIF图像，则会出现错误消息，而不应上传其他五个JPG？

以下是完整代码：

<?php
    if (empty($_FILES['Upload_Property_Images']['name']))
    {
        echo 'You have\'nt Entered Value for upload field'; 
    }
    else
    {
        foreach($_FILES['Upload_Property_Images']['name'] as $file) 
        {
            // Allowed file types
            $whitelist = array("jpg","png");
            $temp = explode('.', $file);
            // Match uploaded file extension
            if (in_array(end($temp), $whitelist )) 
            {
                // Count total uploads
                if (count($_FILES['Upload_Property_Images']['name'])==6) 
                {
                    // Code for uploading here
                    echo 'Image &nbsp;  <b>' .$file.'</b>  &nbsp; uploaded successfully<br>';
                } 
                else 
                {
                    // Count error 
                    echo 'You\'r Only Allowed Six Images';
                    exit();
                }
            } 
            else 
            {
                // File extension error
                echo 'Image  &nbsp;  <b>'.$file.'</b>  &nbsp;  Must be JPG OR PNG<br>';
            }
        }
    }
?>

Answer 1

$errors = array();

if (empty($_FILES['Upload_Property_Images']['name'][0])) {
    $errors[] = 'You have\'nt Entered Value for upload field'; 
}
else {

    if (count($_FILES) > 6)
        $errors[] = "Your Only Allowed Six Images";

    $whitelist = array("jpg","png");

    foreach($_FILES['Upload_Property_Images']['name'] as $file) {
        if ($file) { 

            $temp = explode('.', $file);

            if (!in_array(end($temp), $whitelist )) {
                $errors[] = "All images must be JPG and PNG";
                break;
            }
        }
    }
    if (empty($errors)) {
        foreach ($_FILES['Upload_Property_Images']['name'] as $file) {

            if ($file) {
                // Code for uploading here
                // ...
                echo 'Image &nbsp;  <b>' .$file.'</b>  &nbsp; uploaded successfully<br>';
            }

        }
    }
}

if (!empty($errors))
    foreach ($errors as $e)
        echo $e."<br/>";

如果没有适当的输入，如何阻止此上载脚本执行

1 个答案: