Question

我有一张这样的表：

leave_id  applicant  from_date   to_date    type   status
1             a       2/7/2014   5/7/2014  Annual  Approve
2           Basudev   2/7/2014   5/7/2014  Annual  Approve
3           Basudev   2/7/2014   5/7/2014  Casual  Approve
4           Basudev   2/7/2014   5/7/2014  Sick    Approve
5             a       2/7/2014   5/7/2014  Casual  Approve
6             a       2/7/2014   5/7/2014  Sick    Approve

我想要一份这样的报告：

applicant  annual  casual  sick
   a         2       4      6
Basudev      1       4

我正在使用此查询

select a.applicant,
       case when a.type='Annual' 
         Then (DATEDIFF(to_date,from_date))+1 
         Else '' 
       End as Annual_consume,
       case when a.type='Casual' 
         Then (DATEDIFF(to_date,from_date))+1 
         Else '' 
       End as Casual_consume,
       case when a.type='Sick' 
         Then (DATEDIFF(to_date,from_date))+1 
         Else '' 
       End as Sick_consume 
from leaves a 
order by applicant

但它显示的数据如下：

applicant  annual  casual  sick
   a         2    
   a                 4
   a                        6
Basudev              2
Basudev                     3

请帮助解决此问题。

Answer 1

select a.applicant,
       sum(case when a.type='Annual' Then (DATEDIFF(to_date,from_date))+1 end) as Annual_consume,
       sum(case when a.type='Casual' Then (DATEDIFF(to_date,from_date))+1 end) as Casual_consume,
       sum(case when a.type='Sick' Then (DATEDIFF(to_date,from_date))+1 end) as Sick_consume 
from leaves a 
group by a.applicant
order by a.applicant

Answer 2

SELECT a.applicant,
  SUM(
  CASE
    WHEN a.type='Annual'
    THEN (DATEDIFF(to_date,from_date))+1
  END) AS Annual_consume,
  SUM(
  CASE
    WHEN a.type='Casual'
    THEN (DATEDIFF(to_date,from_date))+1
  END) AS Casual_consume,
  SUM(
  CASE
    WHEN a.type='Sick'
    THEN (DATEDIFF(to_date,from_date))+1
  END) AS Sick_consume
FROM leaves a
ORDER BY applicant
GROUP BY applicant

在sql查询中生成报告的案例问题

2 个答案: