我有一张表来存储员工出勤率,其中包含以下列:
如何编写一个能够出席一个月的查询?
例如:为公司XYZ生成4月份的报告,该报告看起来应该是
StaffName 1 2 3 4 5 6 7 8 9....up to last day of month
--------------------------------------------------------------
John lenon p p p a p a a p a....
Bob Dylan a a a p p p p p a....
Keith Moon p p p p a p a p p....
答案 0 :(得分:0)
您可以使用PIVOT功能将日期转换为列(此处是一个快速而肮脏的示例,您可以检查日期格式和顺序):
SELECT StaffName, [0], [1], [2], [3], [4] and so on...
FROM
(SELECT StaffName, isPresent, date FROM myTable) AS SourceTable
PIVOT
(
MAX(isPresent)
FOR date IN ([0], [1], [2], [3], [4] and so on...)
) AS PivotTable;
答案 1 :(得分:0)
对于动态查询,这可能有点棘手。对于表格:
CREATE TABLE [dbo].[attendance](
[id] [int] NOT NULL,
[StaffName] [varchar](100) NULL,
[CompanyName] [varchar](100) NULL,
[isPresent] [char](1) NULL,
[date] [datetime] NULL,
PRIMARY KEY CLUSTERED ( [id] ASC )
)
go
以下脚本生成'pivot-compatible'脚本,其中包含天数作为列
--report params
DECLARE @month int, @year int, @lastDay int
set @month = 1
set @year = 2012
-- calculations
DECLARE @startDate datetime, @endDate datetime
SET @startDate = convert(varchar, @year) + '-' + convert(varchar, @month) + '-1'
set @endDate = DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@startDate)+1,0))
set @lastDay = day(@endDate) --last day of month
print('showing data from ' + convert(varchar, @startDate) + ' to ' + convert(varchar, @endDate))
print('original report')
SELECT StaffName, isPresent, day([date]) as day FROM attendance
where [date] between @startDate and @endDate
declare @day int
set @day = 2
declare @days varchar(max)
set @days = '[1]'
WHILE (@day <= @lastDay)
BEGIN
set @days = @days + ',[' + convert(varchar, @day) + ']'
set @day = @day + 1
END
-- select @days
declare @query varchar(max)
set @query = '
SELECT StaffName, ' + @days +
'
FROM
(SELECT StaffName, isPresent, day(date) as day FROM attendance) AS SourceTable
PIVOT
(
MAX(isPresent)
FOR day IN ( ' + @days + ')' + '
) AS PivotTable;'
--select @query
print('pivoted report')
exec(@query)