我正在尝试学习外键约束到目前为止我已经能够在mysql中创建外键
了这是我对三个表的创建表查询:
create table customer(
CustId int(100) not null AUTO_INCREMENT primary key,
FirstName varchar(300) default null,
LastName varchar(300) default null,
Gender varchar(200) default null,
Category varchar(200) default null,
DateOfBirth varchar(200) default null,
Age int(3)default null
);
create table address(
Address_Id int(100) not null AUTO_INCREMENT primary key,
Address varchar(1000) default null,
Country varchar(500) default null,
State varchar (500) default null,
city varchar(500)default null,
PinCode int(10)default null,
CustId int(100) not null,
foreign key(CustId) references customer(CustId)
);
create table contact(
Contact_Id int(100) not null AUTO_INCREMENT primary key,
EmailId varchar(500)default null,
ContactNo varchar(20) default null,
MobileNo varchar(20) default null,
CustId int(100) not null,
Address_Id int(100) not null,
foreign key(CustId) references customer(CustId),
foreign key(Address_Id) references address(Address_Id)
);
K现在我知道了,直到这里:
START TRANSACTION;
SET @lid := null;
insert into customer (FirstName,LastName,Gender,Category,DateOfBirth,Age)values('Ashok','sharma','Male','Affiliate','1988-04-17','26');
SELECT LAST_INSERT_ID() INTO @lid;
insert into address(CustId, Address,Country,State,city,Pincode)values (@lid, 'No.1645','India','Karnataka','Bangalore','560060');
COMMIT;
使用事务和提交是解决方案,但如何为联系人表格执行此操作,我有太多的外键。我需要获得两个自动递增的值。
请指导我。
答案 0 :(得分:1)
您可以在多个语句中执行此操作:
START TRANSACTION;
SET @lid := null;
insert into customer (FirstName,LastName,Gender,Category,DateOfBirth,Age)values('Ashok','sharma','Male','Affiliate','1988-04-17','26');
SELECT LAST_INSERT_ID() INTO @lid;
insert into address(CustId, Address,Country,State,city,Pincode)values (@lid, 'No.1645','India','Karnataka','Bangalore','560060');
COMMIT;
对于MySQL 5.1.12及更高版本,没有参数,LAST_INSERT_ID()返回一个64位值,表示由于最近执行的INSERT语句而成功为AUTO_INCREMENT列插入的第一个自动生成的值。
这是会话绑定的,所以不要担心,另一个会话会弄乱你的last_insert_id或其他东西。阅读更多相关信息here。
你最好把它全部放在像我这样的交易中。这可以确保所有语句都成功或不成功,而不仅仅是其中的一部分。你必须使用InnoDB。 MyISAM不支持此功能。或者你忍受风险:)但是因为你使用外键我假设你使用InnoDB,只是想提及它的完整性。
我使用的变量当然可以用PHP变量替换。或者你这样做:
START TRANSACTION;
insert into customer (FirstName,LastName,Gender,Category,DateOfBirth,Age)values('Ashok','sharma','Male','Affiliate','1988-04-17','26');
SELECT LAST_INSERT_ID() INTO @lid;
insert into address(CustId, Address,Country,State,city,Pincode)
SELECT @lid, 'No.1645','India','Karnataka','Bangalore','560060';
COMMIT;
修改强>
START TRANSACTION;
SET @lid_c := null;
SET @lid_a := null;
insert into customer (FirstName,LastName,Gender,Category,DateOfBirth,Age)values('Ashok','sharma','Male','Affiliate','1988-04-17','26');
SELECT LAST_INSERT_ID() INTO @lid_c;
insert into address(CustId, Address,Country,State,city,Pincode)values (@lid, 'No.1645','India','Karnataka','Bangalore','560060');
SELECT LAST_INSERT_ID() INTO @lid_a;
INSERT INTO contact (CustId, Address_Id, another_column) VALUES
(@lid_c, @lid_a, 'another_value');
COMMIT;