Question

我有一个数据框＆＃39; rta＆＃39;有两个日期变量＆＃34; Date.Time of Accident＆＃34;和＆＃34; Date.Time。死亡＆＃34;。变量＆＃39; Date.Time.Death＆＃39;将日期和时间用空格分隔，时间为24小时格式，但在分钟时不均匀。类似地，另一个变量Date.Time.Accident也只是这种格式。

rta <- data.frame(DMYT.Death = c('2008-12-30 10.15','2008-12-15 23','2008-12-15 18.15','2008-12-26 17','2008-12-21 14.45','2008-12-19 23'),stringsAsFactors=F)

我想把这个变量变成YYYY-MM-DD hh：mm的统一格式，例如2008-12-30 10:15，它可以用来计算两个日期变量的生存期。怎么这样做？

Answer 1

rta
##            datevar
## 1 2008-12-30 10.15
## 2    2008-12-15 23
## 3 2008-12-15 18.15
## 4    2008-12-26 17
## 5 2008-12-21 14.45
## 6    2008-12-19 23


# First we add the 'minutes' to strings where they are missing.


rta$datevar[!grepl(".*\\..*", rta$datevar)] <- paste0(rta$datevar[!grepl(".*\\..*", rta$datevar)], ".00")
rta
##            datevar
## 1 2008-12-30 10.15
## 2 2008-12-15 23.00
## 3 2008-12-15 18.15
## 4 2008-12-26 17.00
## 5 2008-12-21 14.45
## 6 2008-12-19 23.00


# Convert the datevar to POSIXct class.
rta$datevar <- as.POSIXct(rta$datevar, format = "%Y-%m-%d %H.%M")
rta
##               datevar
## 1 2008-12-30 10:15:00
## 2 2008-12-15 23:00:00
## 3 2008-12-15 18:15:00
## 4 2008-12-26 17:00:00
## 5 2008-12-21 14:45:00
## 6 2008-12-19 23:00:00

从R中的现有日期变量创建正确的日期和时间变量

1 个答案: