Question

我正在构建一个自动电子邮件系统，作为我设计的会员系统的扩展。

采取以下数组：

array (size=5)
  '002858' => string '<p>These members have expired:</p><p>Adults: None</p><p>Children: Florence Carline</p><p>Disabled Members: None</p>' (length=115)
  '001974' => string '<p>These members have expired:</p><p>Adults: Kelly Hughes, Andrew Hughes</p><p>Children: Alfie Hughes</p><p>Disabled Members: None</p>' (length=134)
  '000033' => string '<p>These members have expired:</p><p>Adults: Kate Shirley</p><p>Children: Rolsin Shirley</p><p>Disabled Members: None</p>' (length=121)
  '000259' => string '<p>These members have expired:</p><p>Adults: Charmaine Walsh, Michael Baxter</p><p>Children: Liam Baxter, George Baxter</p><p>Disabled Members: None</p>' (length=152)
  '000000' => string '<p>These members are expiring in a month:</p><p>Adults: Edward Selby</p><p>Children: None</p><p>Disabled Members: None</p>' (length=122)

当我尝试在foreach循环中读取数组时（每封电子邮件一次迭代），我收到以下错误：

Notice: Uninitialized string offset: 1974 in C:\wamp\www\subdomains\[host]\controllers\email.class.php on line 145

请注意，这是我的数组中的第二个，但没有'00'。

我看过这个：php array behaving strangely with key value 07 & 08

所以我检查了（使用is_int（）） - 键是一个非int的字符串。

有人能为我解释一下吗？

编辑：

创作：

foreach($email_list_array['month'] as $key => $ticket) {

    $header[$key] =  "<p>Our records indicate that your pass (ticket number: $key) is expiring or has already expired.</p>";
    $header[$key] .= "<p>Please see the details below</p>";

    if(!isset($message[$key])) {
        $message[$key] = "<p>These members are expiring in a month:</p>";
    } else {
        $message[$key] .= "<p>These members are expiring in a month:</p>";
    }

    $message[$key] .= "<p>Adults: $adults</p>";
    $message[$key] .= "<p>Children: $children</p>";
    $message[$key] .= "<p>Disabled Members: $disabled</p>";

}

这是我进行阵列转储的地方

var_dump($message);

测试输出：

foreach($message as $key => $value) {

    $message_header = $header[$key];
    $message = $message[$key];

    echo $message_header;
    echo $message;
    echo "<br>";

}

Answer 1

在foreach中更改变量$ message的名称：

$messageXXX = $message[$key];
echo $messageXXX;

Answer 2

我猜这个数组是作为整数访问而不是字符串。所以你应该将整数转换为字符串。

请注意，整数访问和字符串访问之间存在差异！

$arrayX = array( "A", "X" );
$arrayY = array( "0012"=> "A", "0001"=>"b" );


print_r( $arrayX );

print_r( $arrayY);

echo "array X ". $arrayX[1];  // returns "X"
echo "array Y".$arrayY["0012"];  // returns "A"
echo "array Y ".$arrayY[12];       // should also return "A"

输出如下

Array
(
    [0] => A
    [1] => X
)
Array
(
    [0012] => A
    [0001] => b
)
XA
Notice: Undefined offset: 12 in /test.php on line 14

在您的情况下，您还需要添加类似

的前导零

$value = 12; // integer
$str = sprintf("%04d",$value);  // now $str = "0012"
echo "array Y ".$arrayY[ $str ];       // now returns "A"

Answer 3

您的部分问题是您在循环中为$message分配了值，但$message是您的输入变量。这使得PHP正在做它正在做的事情。您似乎也试图从两个不同的阵列中获取相同的密钥。这是对的吗？

无论如何看看以下内容：

foreach($message as $key => $value) {

    $message_header = $header[$key];
    $messageText = $message[$key];

    echo $message_header;
    echo $messageText;
    echo "<br>";

}

这有望显示您在测试中需要进行哪些更改以阻止错误发生。

PHP删除前导零

3 个答案: