Question

我无法打印更改列表。每次我运行我的脚本并检查值时，它都是空白的。

postcommithook.bat
set REPOS=%1
set REV=%2
set TXN_NAME=%3
set LF = ^

SET ThisScriptsDirectory=%~dp0

set svnlook = "C:\Program Files\TortoiseSVN\bin\"

for /f "tokens=*" %%a in ('%svnlook% svnlook author -r %REV% %REPOS%') do set AUTH_NAME=%%a

setlocal enabledelayedexpansion

set MSG = for /f %%i in ('svnlook changed -r %REV% %REPOS%') do (
SET "VAR=!VAR!!LF%%i"
SET "PAR=!PAR!^^!LF!!LF!%%i"
)
set DIRS_CHANGED = !VAR!
endlocal

SET PowerShellScriptPath=%ThisScriptsDirectory%emailer.ps1
PowerShell -NoProfile -ExecutionPolicy Bypass -Command "& '%PowerShellScriptPath%' '%REPOS%' '%REV%' '%TXN_NAME%' '%AUTH_NAME%' '%DIRS_CHANGED%'";

我知道我在循环中的某个地方犯了一个错误，我在调用change函数。如何获取已更改目录的列表并将其传递给邮件程序脚本？

提前致谢

Answer 1

在这里回答我自己的问题：我已经删除了命令'svn changed'完成的循环。相反，我将输出存储在一个单独的文件中，然后通过powershell / vbscript文件开始处理它，以生成电子邮件。

取代以下内容：

svnlook changed %REPOS% -r %REV% > %ThisScriptsDirectory%tmp_log.txt

而不是

setlocal enabledelayedexpansion
set MSG = for /f %%i in ('svnlook changed -r %REV% %REPOS%') do (
SET "VAR=!VAR!!LF%%i"
SET "PAR=!PAR!^^!LF!!LF!%%i"
)
set DIRS_CHANGED = !VAR!
endlocal

谢谢， Venkat。

SVNLOOK在postcommit hook-batch文件中更改

1 个答案: