这是我的代码，它应该是用户添加，乘法，除法或减去两个整数。当我执行它时，我可以输入整数和运算符，甚至可以输入＆＃39;字符串打印出来但不是打印出问题的实际答案，而是说“分段故障（核心转储）”。我知道当程序试图使用或写入它无法访问的内存时会发生这种情况。我是汇编语言的新手，我花了很长时间才能做到这一点。请帮我。
1 ; Function: adds, subtracts, divides or multiplies two
2 ; integers the user inputs
3 ;
4 ;
5 ; -------------------------------------------------------------------------- --
6
7 %include "CPsub32.inc"
8 %include "Macros_CPsub32.inc"
9
10 section .data
11
12 CRLF db 0Ah,0Dh,00h
13 prompt1 db 0Ah,0Dh,'Please enter an Integer?',0Ah,0Dh,00h
14 prompt2 db 0Ah,0Dh,'Please enter an Operator?',0Ah,0Dh,00h
15 answer db 0Ah,0Dh,'The answer is: ',0Ah,0Dh,00h
16
17 operand1 DD 0d
18 operand2 DD 0d
19 operator db 00h
20 result DD 0d
21
22
23 ipbuffer db " "
24 ipbuflen equ $-ipbuffer
25
26
27 section .text
28 global main
29
30 main equ $
31 mov edx, prompt1 ;move prompt1 to reg edx
32 call WriteString ;write out prompt1
33 mov edx, ipbuffer
34 mov ecx, ipbuflen
35
36 call ReadString ;read users input (operand1)
37 mov edx, ipbuffer
38 mov ecx, 4 ;something with 4 bytes in reg ecx
39 call ParseDecimal32 ;change users input (op1) into decim al
40 mov dword [operand1], eax ;load user input (op1) into operand1 ?
41
42 mov edx, prompt2 ;move prompt2 to reg edx
43 call WriteString ;write out prompt2
44 mov edx, ipbuffer
45 mov ecx, ipbuflen
46
47 call ReadString ;read user input (operator)
48 mov edx, [ipbuffer]
49 mov [operator], dl ;move user input (operator) to opera tor
50
51 mov edx, prompt1 ;move prompt1 to reg edx again
52 call WriteString ;write out promt1 again
53 mov edx, ipbuffer
54 mov ecx, ipbuflen
55
56 call ReadString ;read users input (operand2)
57 mov edx, ipbuffer
58 mov ecx, 4 ;something with 4 bytes in reg ecx
59 call ParseDecimal32 ;change user input (op2) into decima l
60 mov dword [operand2], eax ;move user input (op2) into operand2 ?
61
62 mov edx, answer ;move answer to reg edx
63 call WriteString ;write out "answer is"
64 mov edx, ipbuffer
65 mov ecx, ipbuflen
66
67 mov dl, [operator] ;move operator to dl
68 mov eax, [operand1] ;move operand1 to eax
69 mov ebx, [operand2] ;move operand2 to ebx
70
71
72 cmp dl, 2Bh ;is this a + sign
73 je myAdd
74 cmp dl, 2Dh ;is this a - sign
75 je mySub
76 cmp dl, 2Ah ;is this a * sign
77 je myMul
78 cmp dl, 2Fh ;is this a / sign
79 je myDiv
80
81 mov eax, [result] ;mov result to reg eax
82 call WriteString ;write out the result
83 mov edx, ipbuffer
84 mov ecx, ipbuflen
85
86 jmp myExit
87
88 myAdd equ $
89 add eax,ebx ;add operand1 and operand2
90 mov dword[result],eax ;move sum to result
91
92 mySub equ $
93 sub eax,ebx ;subtract operand1 and operand2
94 mov dword [result], eax
95
96 myDiv equ $
97 mov ecx, ebx
98 div byte[ecx] ;divide operand1 by operand2
99 mov dword [result], eax
100
101 myMul equ $
102 xor edx,edx
103 mul byte[ebx] ;multiply operand1 and operand2
104 mov dword [result], eax
105
106 myExit equ $