Question

我正在尝试查询数据库：

获取足球比赛记录
获取属于该比赛的所有球员

有三个表：Matches | Players | Match_Players

Match_Players只是将其他两个表连接在一起。

我正在尝试以JSON格式返回结果。

问题在于第二个查询。它返回Errant Query。这就是我到目前为止所做的：

$matches = array();
if(mysql_num_rows($matchResult)) 
{
    while($match = mysql_fetch_assoc($matchResult)) 
    {
        $players_query = 
            "SELECT p.* FROM match_players mp 
            LEFT JOIN players p on p.id = mp.player_id
            WHERE mp.id = ".$match->player_id; // <--- This is the error

        $playersResult = mysql_query($players_query,$link) or die('Errant query: '.$players_query);
        $players       = array();

        if(mysql_num_rows($playersResult)) 
        {
            while($player = mysql_fetch_assoc($playersResult)) 
            {
                $players[] = $player;
            }
        }

        $match->$players = $players;    
        $matches[] = $match;
    }
}

更新

我已将$match->player_id替换为$match['player_id'];，从而更改了第二个SQL语句。然而，我没有收到玩家的集合。我只能看到比赛的详细信息。知道为什么吗？

Answer 1

使用

$match['player_id']

（数组语法）不是

$match->player_id

（对象语法）或使用

mysql_fetch_object

虽然我希望你应该做一个查询，而不是循环

Answer 2

查询不应该是这样的吗？

"SELECT p.* 
FROM match_players mp 
RIGHT JOIN players p on p.id = mp.player_id
WHERE mp.match_id = ".$match->id;

或者像这样

"SELECT p.*
FROM players p, match_players mp, matches m
WHERE p.id = mp.player_id AND mp.match_id = m.id
AND m.id = ". $match->id;

创建了sqlfiddle来尝试检查查询，它们很好......

PHP将数组添加到对象

2 个答案: