Question

这是我的问题。我有一个像这样的JSON文件：

[
{
    "projectName": "test",
    "clientName": "test2",
    "dateValid": "2014-04-18",
    "account": {
        "accountAmount": null,
        "accountDate": "2014-04-19",
        "accountType": null
    },
    "total": {
        "totalAmount": null,
        "totalDate": "2014-04-18",
        "totalType": null
    }
}]

我希望PHP打开这个文件并添加另一个对象，所以我的文件将如下所示：

[
    {
        "projectName": "test",
        "clientName": "test2",
        "dateValid": "2014-04-18",
        "account": {
            "accountAmount": null,
            "accountDate": "2014-04-19",
            "accountType": null
        },
        "total": {
            "totalAmount": null,
            "totalDate": "2014-04-18",
            "totalType": null
        }
    },
    {
        "projectName": "test",
        "clientName": "test2",
        "dateValid": "2014-04-18",
        "account": {
            "accountAmount": null,
            "accountDate": "2014-04-19",
            "accountType": null
        },
        "total": {
            "totalAmount": null,
            "totalDate": "2014-04-18",
            "totalType": null
        }
    }
]

应该很简单，但我无法做到。我尝试了多种方法：

$file = 'base.json';
if(file_exists ($file)){
    echo 'base.json found';
    $fileContent = file_get_contents($file);
    $oldData = json_decode($fileContent, true);
    echo var_export($oldData);
}
else {
    echo 'base.json not found';
    $oldData = [];
}


echo $data;
$data = json_encode($data);
$oldData = json_encode($oldData);
echo $data; // debug
file_put_contents('base.json', '['.$data.','.$oldData.']');

是的，我投入了大量的回音调试数据流程......我缺少什么？

Answer 1

你将此视为字符串操作，这是一种错误的方法。您需要在两个结构对象时将它们组合在一起，之前将它们重新编码为JSON。

这三行......

$data = json_encode($data);
$oldData = json_encode($oldData);
file_put_contents('base.json', '['.$data.','.$oldData.']');

应改写为......

// Create a new array with the new data, and the first element from the old data
$newData = array($data, $oldData[0]);
$newData = json_encode($newData);
file_put_contents('base.json', $newData);

Answer 2

使用以下命令将新数据添加到数组中：

$oldData[] = $data;

然后将其写回文件：

file_put_contents('base.json', json_encode($oldData));

Answer 3

您可以将json var转换为数组，在json_decode上将第二个param指定为true，并在使用array_merge包含新数组var并再次转换为json之后。

<?php
$json1 = '[{
    "projectName": "test",
    "clientName": "test2",
    "dateValid": "2014-04-18",
    "account": {
        "accountAmount": null,
        "accountDate": "2014-04-19",
        "accountType": null
    },
    "total": {
        "totalAmount": null,
        "totalDate": "2014-04-18",
        "totalType": null
    }
}]';

$json2 = '[{
    "projectName": "test 2",
    "clientName": "test3",
    "dateValid": "2014-04-22",
    "account": {
        "accountAmount": null,
        "accountDate": "2014-04-27",
        "accountType": null
    },
    "total": {
        "totalAmount": null,
        "totalDate": "2014-04-27",
        "totalType": null
    }
}]';

$arr1 = json_decode($json1, true);
$arr2 = json_decode($json2, true);

$json2 = json_encode(array_merge($arr1, $arr2));

?>

Answer 4

试试这个

$arr = json_decode(file_get_contents('myFile.json'));

// append a new "object" (array)
$arr[] = array(
    "projectName" => "test",
    "clientName" => "test2",
    "dateValid" => "2014-04-18",
    "account" => array(
        "accountAmount" => null,
        "accountDate" => "2014-04-19",
        "accountType" => null
    ),
    "total" => array(
        "totalAmount" => null,
        "totalDate" => "2014-04-18",
        "totalType" => null
    )
);

$json = json_encode($arr);

file_put_contents('myFile.json', $json);

Answer 5

试试这个：

<?php


$json = '[
{
    "projectName": "test",
    "clientName": "test2",
    "dateValid": "2014-04-18",
    "account": {
        "accountAmount": null,
        "accountDate": "2014-04-19",
        "accountType": null
    },
    "total": {
        "totalAmount": null,
        "totalDate": "2014-04-18",
        "totalType": null
    }
}]';

$json_to_add=' {
        "projectName": "test",
        "clientName": "test2",
        "dateValid": "2014-04-18",
        "account": {
            "accountAmount": null,
            "accountDate": "2014-04-19",
            "accountType": null
        },
        "total": {
            "totalAmount": null,
            "totalDate": "2014-04-18",
            "totalType": null
        }
    }';

$data = json_decode($json);
$data_to_add = json_decode($json_to_add);
$data[]=$data_to_add ;
var_dump($data);

使用PHP将新的JSON对象添加到数组中

5 个答案: