Question

我正在尝试将记录为TEXT的两个时间值转换为数值，以便在计算中用于计算差异，这将在视图中实现。

我目前的尝试如下。

CREATE VIEW TimeTakenSwimming AS 
SELECT UserDetails.username AS username, 
       SwimmingRecords.distance_in_miles AS distance, 
       SwimmingRecords.start_time AS starttime, 
       SwimmingRecords.end_time AS endtime, 
       sum((strftime('%s', end_time) - strftime('%s', start_time)) AS timedifference,
FROM UserDetails INNER JOIN SwimmingRecords ON UserDetails.username = SwimmingRecords.username;

现在，我正在接受与＆＃34; AS＆＃34;相关的错误。句法。我已经通过并纠正了任何缺失的空格，从SUM计算中添加了缺少的括号等，但是在实现时我仍然收到所述的语法错误。

下面是与我的架构相关的代码，允许其他人尝试复制该问题，我已经使用SQLite管理器Firefox插件来实现此系统。

CREATE TABLE "UserDetails" (
    "username" TEXT PRIMARY KEY  NOT NULL  UNIQUE  CHECK (length(username)>0), 
    "password" TEXT NOT NULL  CHECK (length(password)>3), 
    "email_address" TEXT NOT NULL  UNIQUE CHECK (length(email_address)>3) , 
    "weight_in_pounds" REAL NOT NULL CHECK(weight_in_pounds>0) CHECK (length(weight_in_pounds)>0), 
    "height_in_inches" REAL NOT NULL CHECK(height_in_inches>0) CHECK (length(height_in_inches)>0), 
    "age" INTEGER CHECK(age>0), WITHOUT ROWID
    )

CREATE TABLE "SwimmingRecords" (
    "record_ID" INTEGER PRIMARY KEY  AUTOINCREMENT  NOT NULL  UNIQUE CHECK (record_ID>0) , 
    "distance_in_miles" REAL NOT NULL CHECK (distance_in_miles>0) , 
    "num_of_lengths" REAL NOT NULL CHECK(num_of_lengths>0), "username" TEXT NOT NULL , 
    "date" DATETIME DEFAULT CURRENT_DATE, "notes" TEXT(50), 
    "start_time" TEXT, 
    "end_time" TEXT, 
    FOREIGN KEY(distance_in_miles) REFERENCES DistanceinMiles(distance_in_miles) ON DELETE CASCADE ON UPDATE CASCADE, 
    FOREIGN KEY(num_of_lengths) REFERENCES NumberOfLengths(num_of_lengths) ON DELETE CASCADE ON UPDATE CASCADE,
    FOREIGN KEY(username) REFERENCES UserDetails(username)ON DELETE CASCADE ON UPDATE CASCADE
    )

我提前感谢您的任何帮助。

Answer 1

sum后括号太多，FROM之前有错误的逗号：

CREATE VIEW ...
SELECT ...,
       sum(strftime('%s', end_time) - strftime('%s', start_time)) AS timedifference
FROM ...;

将文本时间转换为数字

1 个答案: