Question

我已经构建了以下查询以尝试＆amp;执行以下操作：

如果omSchedDate =今天的0到30天，则标记＆＃34; 30天＆＃34;
如果omSchedDate =今天的31至60天，则标记＆＃34; 60天＆＃34;

如果omSchedDate在今天的0天之前或在60天之后，则标记＆＃34; Not Scheduled＆＃34;

SELECT DATEDIFF(tblcom.omSchedDate, CURDATE()) AS age,

CASE 
WHEN tblcom.omSchedDate > CURDATE() AND tblcom.omSchedDate < (DATE_ADD(CURDATE(),
INTERVAL 31 DAY))THEN '30 Days'
WHEN DATEDIFF(CURDATE(), tblcom.omSchedDate) > 30 THEN '60 Days'
WHEN DATEDIFF(CURDATE(), tblcom.omSchedDate) <= 0 then 'Not Scheduled'
WHEN DATEDIFF(CURDATE(), tblcom.omSchedDate) IS NULL then 'Not Scheduled'
ELSE NULL
END AS consch

FROM      tblcom 
ORDER BY tblcom.omSchedDate

上面的我的查询为我提供了30天列的正确输出，但是＆＃34; 60天＆＃34; ＆安培; ＆＃34;未计划＆＃34;列不正确？

Age, conSch
-728,60 Days
-726,60 Days
-715,60 Days
-666,60 Days
-102,60 Days
-88,60 Days
-46,60 Days
-15,
-14,
-5,
-4,
2,30 Days
3,30 Days
6,30 Days
14,30 Days
27,30 Days
28,30 Days
30,30 Days
41,Not Scheduled
41,Not Scheduled
83,Not Scheduled
188,Not Scheduled

Answer 1

这里有很多问题。首先，在DATEDIFF操作中，您的减法顺序相反。它应该是：

WHEN DATEDIFF(omSchedDate, CURDATE()) > 30 THEN '60 Days'
WHEN DATEDIFF(omSchedDate, CURDATE()) < 0 THEN 'Not Scheduled'

其次，您没有检查差异超过60天，因此您需要添加该AND并且需要在检查前添加它超过30天，否则大于60的值将永远不会达到那个检查。

WHEN DATEDIFF(omSchedDate, CURDATE()) > 60 THEN 'Not Scheduled'

第三，如果omSchedDate可能为NULL（这是你的最终DATEDIFF行最终为空的唯一方式），那么你应该首先检查它以防止可能的错误：

CASE
WHEN omSchedDate IS NULL THEN 'Not Scheduled'

您也可以将您的其他行翻译为DATEDIFF，并留下：

CASE
    WHEN omSchedDate IS NULL THEN 'Not Scheduled'
    WHEN DATEDIFF(omSchedDate, CURDATE()) BETWEEN 0 AND 30 THEN '30 Days'
    WHEN DATEDIFF(omSchedDate, CURDATE()) > 60 THEN 'Not Scheduled'
    WHEN DATEDIFF(omSchedDate, CURDATE()) > 30 THEN '60 Days'
    WHEN DATEDIFF(omSchedDate, CURDATE()) < 0 THEN 'Not Scheduled'
    ELSE NULL
END AS consch

MySQL查询案例适用于30天，60天和未计划的输出

1 个答案: