转动长度X的字符串 - ＆gt;长度Y.

Question

我在变量x和y中有两个字符串，其中x的长度大于y的长度。如何将较小的字符串（y）映射到大字符串（x）的大小？

例如：

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"

while len(y) < len(x):
    y+=y
while len(y) > len(x):
    y = y[:-1] 

print x 
print y 

appleappleapple
abcabcabcabcabc

是否有一种非常pythonic /有效的方法来进行此操作？

Answer 1

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"
z = (y*(len(x)/len(y)+1))[:len(x)]